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3 years ago

11

The small intestine shown below contains lymphatic vessels but no capillaries. Which nutrient will be absorbed by this small int

estine?
A-Simple carbohydrates
B- Amino acids
C-Fatty acids
D-All of the above

2 answers:

Bumek [7]3 years ago

8 0

Answer:

fatty acids

Explanation:

masya89 [10]3 years ago

6 0

Answer:

D

Explanation:

D is the answer

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What is Lewis symbol for K+

Alexxx [7]

Lewis symbol for K+ is given by a dot and K.

<h3>Meaning of Lewis symbol</h3>

Lewis symbols can be defined as a symbol the is used in describing the valence electron configurations of an atom ions.

A Lewis symbol consists of the symbol of the element and then surrounded by one dot for each of its valence electrons.

In conclusion, Lewis symbol for K+ is given by a dot and K.

Learn more about Lewis symbol: brainly.com/question/6605265

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2 years ago

When 2 crystalline solid barium hydroxide octahydrate and crystalline solid ammonium nitrate are mixed in a beaker at room tempe

podryga [215]

It is endothermic reaction ΔH>0 (sign is +).
Because it is spontaneous reaction ΔG<span><0 (Gibbs free energy)
</span>ΔG=ΔH-TΔS, so must be TΔS>ΔH and ΔS<span>>0 (sign +).</span>

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3 years ago

Formal charge of Cl in CHCl3

Vsevolod [243]

FC(C) = 4 - 0.5*8 - 0 = 0) FC(Cl) = 7 - 0.5*2 - 6 = 0

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3 years ago

Consider the reaction 4PH3(g) → P4(g) + 6H2(g) At a particular point during the reaction, molecular hydrogen is being formed at

Svetllana [295]

Answer:

The rate at which $P_4$ is being produced is 0.0228 M/s.

The rate at which $PH_3$ is being consumed is 0.0912 M/s.

Explanation:

$4PH_3\rightarrow P_4(g)+6H_2(g)$

Rate of the reaction : R

$R=\frac{-1}{4}\frac{d[PH_3]}{dt}=\frac{1}{6}\frac{d[H_2]}{dt}=\frac{1}{1}\frac{d[P_4]}{dt}$

The rate at which hydrogen is being formed = $\frac{d[H_2]}{dt}=0.137 M/s$

$R=\frac{1}{6}\frac{d[H_2]}{dt}$

$R=\frac{1}{6}\times 0.137 M/s=0.0228 M/s$

The rate at which $P_4$ is being produced:

$R=\frac{1}{1}\frac{d[P_4]}{dt}$

$0.0228 M/s=\frac{1}{1}\frac{d[P_4]}{dt}$

The rate at which $PH_3$ is being consumed :

$R=\frac{-1}{4}\frac{d[PH_3]}{dt}$

$0.0228 M/s\times 4=\frac{-1}{1}\frac{d[PH_3]}{dt}$

$\frac{-1}{1}\frac{d[PH_3]}{dt}=0.912 M/s$

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3 years ago

Which of the following elements has the lowest electronegativity?

Readme [11.4K]

A. lithium
there ya go

3 0

3 years ago