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Gre4nikov [31]
2 years ago
8

Please help ASAPPPPPPPPPPPPPPP

Chemistry
1 answer:
RUDIKE [14]2 years ago
6 0
D AHHAHAHA DNKWPAKHEBW
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Consider the following intermediate chemical equations.
QveST [7]

Answer: 250 kJ

Explanation: According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

P_4(s)+6Cl_2\rightarrow 4PCl_3  \Delta H_1=-2439kJ (1)

4PCl_5(g)\rightarrow P_4(s)+10Cl_2(g)  \Delta H_2=3438kJ (2)

Net chemical equation:

PCl_5(g)\rightarrow PCl_3(g)+Cl_2(g)  \Delta H=? (3)

Adding 1 and 2 we get,

4PCl_5(g)\rightarrow 4PCl_3(g)+4Cl_2 \Delta H_3=\Delta H_1+\Delta H_2=-2439+3438=1000kJ   (4)

Now dividing equation (4) by 4, we get

PCl_5(g)\rightarrow PCl_3(g)+Cl_2

\Delta H=\frac{\Delta H_3}{4}=\frac{1000kJ}{4}=250kJ   (4)

8 0
2 years ago
Which of the following is an example of kinetic energy?
deff fn [24]

Answer:

A. The energy of moving particles near a fire

Explanation:

7 0
3 years ago
Carbon-14 has a half-life of 5,730 years. It is used in "carbon dating" to determine the age of once living organisms. How much
Nookie1986 [14]

Answer:

18 grams

Explanation:

Because 17,190 yrs divided by the amount of years it takes for a half-life to occur is 3. So 3 half life’s happen, so you divide 144/2 once, equaling 72. You divide 72/2 again (another half-life) and you get 36. You then calculate the third half life by dividing 36/2 which equals 18 grams.

7 0
2 years ago
Under what conditions is the change in internal energy, δe rxn , equal to the heat evolved in a chemical reaction?
Stells [14]
 the first law says that  the change in internal energy of a system is given by: 

δ<span>E = δq + δw</span>

where δ<span>E is the i change in internal energy, </span>

<span>δq is the amount of thermal energy added to the system from the surroundings </span>

<span>δw is the l work done *on* the system *by* the surroundings. </span>

<span>For a system only undergoing expansion work,
δw = -p</span>δ<span>V, so: </span>

δE = δq - p δ<span>V </span>
when δV = 0, then δe=δq
4 0
2 years ago
Balance the following chemical reaction. ____NaOH+____H2SO4 → ___Na2SO4+____H2O
kobusy [5.1K]
The balanced equation would be 2NaOH + H2SO4 → Na2SO4 + 2H2O
7 0
2 years ago
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