Bam added 8.91 g of CsCl to 34.29 mL of H2O. Calculate the concentration of Bam's solution in units of g solute/100 g solvent.
1 answer:
The concentration of the solution is .
We have 34.29 mL of water, whose density is 0.9975 g/mL. The corresponding mass of water is:
8.91 g of CsCl (solute) are in 34.20 g of water (solvent). We can calculate the concentration of Bam's solution in units of g solute/100 g solvent, using the following expression.
The concentration of the solution is .
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Answer:
The carbocation intermediate reacts with a nucleophile to form the addition product.
Explanation:
The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.
The general mechanism is shown in the figure.
i) Attack of the electrophile on the benzene (which is the nucleophile)
ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.
iii) the carbocation formation is the rate determining step.
iv) There is no formation of addition product.
Thus the wrong statement is
The carbocation intermediate reacts with a nucleophile to form the addition product.
