Bam added 8.91 g of CsCl to 34.29 mL of H2O. Calculate the concentration of Bam's solution in units of g solute/100 g solvent.
1 answer:
The concentration of the solution is .
We have 34.29 mL of water, whose density is 0.9975 g/mL. The corresponding mass of water is:
8.91 g of CsCl (solute) are in 34.20 g of water (solvent). We can calculate the concentration of Bam's solution in units of g solute/100 g solvent, using the following expression.
The concentration of the solution is .
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Answer: 0.172 M
Explanation:
a) To calculate theconcentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
b) To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
The concentration of the phosphoric acid solution is 1.172 M