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Naddika [18.5K]
3 years ago
10

Police are investigating an accident. They know that Tom Brady was driving 20 m/s before being hit by Jay Z head on. Tom Brady’s

car has a mass of 1100 kg and Jay Z’s has a mass of 1475 kg. They also know that the two cars stuck together and were traveling 7 m/s in the same direction as Jay Z was driving. The speed limit was 25 m/s, was Jay Z speeding?
Please show work
Physics
1 answer:
Katarina [22]3 years ago
5 0

Answer:

Yes

Explanation:

Momentum before collision = momentum after collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

The cars stick together after the collision, so they have the same final velocity.

m₁u₁ + m₂u₂ = m₁v + m₂v

m₁u₁ + m₂u₂ = (m₁ + m₂)v

Plug in values and solve (take Jay Z's direction to be positive):

(1100) (-20) + (1475) u₂ = (1100 + 1475) (7)

u₂ = 27.1 m/s

Yes, Jay Z was speeding.

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Can you find the magnetic field based on force? a straight segment of wire 35.0 cm long carrying a current of 1.40 a is in a uni
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The force exerted by a magnetic field on a wire carrying current is:
F=ILB \sin \theta
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In our problem, the force is F=0.20 N. The current is I=1.40 A, while the length of the wire is L=35.0 cm=0.35 m. The angle between the wire and the magnetic field is 53 ^{\circ}, so we can re-arrange the formula and substitute the numbers to find B:
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A charged particle is placed in an external magnetic field and it is moving in a circular path of radius 26m.The magnetic force
ElenaW [278]

Answer:

208 Joules

Explanation:

The radius of the circular path the charge moves, r = 26 m

The magnetic force acting on the charge particle, F = 16 N

Centripetal force, F_c = m·v²/r

Kinetic energy, K.E. = (1/2)·m·v²

Where;

m = The mass of the charged particle

v = The velocity of the charged particle

r = The radius of the path of the charged particle

Whereby the magnetic force acting on the charge particle = The centripetal force, we have;

F = F_c = m·v²/r = 16 N

(1/2) × r × F_c = (1/2) × r × m·v²/r = (1/2)·m·v² = K.E.

∴ (1/2) × r × F_c = (1/2) × 26 m × 16 N =  = (1/2)·m·v² = K.E.

∴ 208 Joules = K.E.

The kinetic energy of an particle moving in the circular path, K.E. = 208 Joules.

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A train moves moves from rest to a speed of 25 m/s in 30.0 sec . what is its acceleration
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A = Delta v/Delta t
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