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finlep [7]
3 years ago
8

How do you find motion

Physics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer:

idk you got me there

Explanation:

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A 35.9 g mass is attached to a horizontal spring with a spring constant of 18.4 N/m and released from rest with an amplitude of
lidiya [134]

Answer:

7.74m/s

Explanation:

Mass = 35.9g = 0.0359kg

A = 39.5cm = 0.395m

K = 18.4N/m

At equilibrium position, there's total conservation of energy.

Total energy = kinetic energy + potential energy

Total Energy = K.E + P.E

½KA² = ½mv² + ½kx²

½KA² = ½(mv² + kx²)

KA² = mv² + kx²

Collect like terms

KA² - Kx² = mv²

K(A² - x²) = mv²

V² = k/m (A² - x²)

V = √(K/m (A² - x²) )

note x = ½A

V = √(k/m (A² - (½A)²)

V = √(k/m (A² - A²/4))

Resolve the fraction between A.

V = √(¾. K/m. A² )

V = √(¾ * (18.4/0.0359)*(0.395)²)

V = √(0.75 * 512.53 * 0.156)

V = √(59.966)

V = 7.74m/s

8 0
2 years ago
Read 2 more answers
1. The matter a wave travels through is called a
Luba_88 [7]
It is called a medium
3 0
3 years ago
What is wrong with the following statement: When you exert a force on a baseball, the equal and opposite force on the ball balan
gregori [183]

Answer:

When you exert a force on a baseball, there exists an equal and opposite force on the ball therefore, the ball will accelerate in opposite direction.

Explanation:

When you hit a ball with baseball bat, the bat exerts a great force on the ball which causes the ball to accelerate in the opposite direction. It is to be noted that the mass of bat is much greater than mass of ball but the acceleration of ball is also greater than the acceleration of the bat so both bat and ball almost exert same magnitude of force but in opposite direction and as a result both bat and ball accelerate in opposite direction, the deciding factor is of course the relative force applied by the batter and the bowler.

6 0
3 years ago
A lamp is rated for 240v,2.5A.what is the cost of using the lamp for 3hrs if 1kWh of electricity cost #12​
marshall27 [118]

Answer:

≈ 22¢

Explanation:

240 / 1000 = 0.240 kV

0.240 kV(2.5 A)(3 hr) = 1.8 kW•hr

1.8 kW•hr($0.12/kW•hr) = $0.216

6 0
3 years ago
Please help if you can.
VMariaS [17]

Initially there were 10 bulbs of 60 Watt power

So total power of all bulbs = 60 * 10 = 600 W

now each bulb used for 4 hours daily

so total energy consumed daily

E = P * t

E = 600 * 4 = 2400 Wh

E = 2.4 kWh

now we have total power consumed in 1 year

E = 365 * 2.4 = 876 kWh

cost of electricity = 10 cents/ kWh

so total cost of energy for one year

P_1 = 876 * 10 = 8760 cents = $87.60

Now if all 60 Watt bulbs are replaced by 30 Watt bulbs

So total power of all bulbs = 30 * 10 = 300 W

now each bulb used for 4 hours daily

so total energy consumed daily

E = P * t

E = 300 * 4 = 1200 Wh

E = 1.2 kWh

now we have total power consumed in 1 year

E = 365 * 1.2 = 438 kWh

cost of electricity = 10 cents/ kWh

so total cost of energy for one year

P_1 = 438 * 10 = 4380 cents = $43.80

total money saved in 1 year

Savings = 87.6 - 43.8 = $43.80

3 0
3 years ago
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