Answer:
Explanation:
Given that,
Current in loops are
i1 = 12A
i2 = 20A
The loops are 3.4cm apart
The magnetic field at the center is found to be zero, so when want to find the radius of bigger loop
Magnetic Field is given as
B= μoi/2πr
Where,
μo is a constant = 4π×10^-7 Tm/A
r is the distance between the two wires
i is the current in the wires
B is the magnetic field
NOTE
Field due to large loop should be equal to the smaller loop.
B1 = B2
μo•i1 / 2π•r1 = μo•i2 / 2π•r2
Then, μo, 2π cancels out, so we have
i1 / r1 = i2 / r2
Make r2 subject of formula
i1•r2 = i2•r1
r2 = i2•r1 / i2
r2 = 20×3.4/12
r2 = 5.67cm
The radius of the bigger loop is 5.67cm.
That is 164.592cm = 5.4 feet
If it does do it then yeah it will for it
The rate constant of a reaction can be computed by the ratio of the changes in the concentration and time take taken for it to decompose. Thus, if the rate constant is given to be 14 M/s, we have
![rate = \frac{-(C_{new} - C_{old})}{t}](https://tex.z-dn.net/?f=%20rate%20%3D%20%5Cfrac%7B-%28C_%7Bnew%7D%20-%20C_%7Bold%7D%29%7D%7Bt%7D%20)
where C are the concentration values and t is the time taken for it to decompose.
![14 = \frac{-(0.02 - 0.06)}{t}](https://tex.z-dn.net/?f=%2014%20%3D%20%5Cfrac%7B-%280.02%20-%200.06%29%7D%7Bt%7D%20)
![t = 0.003 s](https://tex.z-dn.net/?f=%20t%20%3D%200.003%20s%20)
Thus, it will take 0.003 s for it to decompose.
Answer: 0.003 s
Answer:
Vf=3
Explanation:
you must first write your data
data before impact
M1=1000 M2=5000
V1=0 m/s V2 =0m/s
data after impact
M1=1000 M2=5000
V1=15m/s V2=?
M1V1 +M2V2=M1V1 +M2V2f
(1000)(0)+(5000)(0)=(1000)(15)+(5000)Vf
0=15000+5000Vf
- 15000÷5000=5000Vf÷5000
Vf= -3
Vf =3