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valentinak56 [21]
3 years ago
12

At constant temperature and pressure, 5.0 L of SO2 is

Chemistry
1 answer:
Ne4ueva [31]3 years ago
4 0
I've done this a few times and keep coming up with 5.0 L . I used the mole ratio, and SO 2 as the LR. That would make 2 moles of SO3 5.0 L but its not one of your choices. the temp and pressure are constant, so according to n/v = p/rt the volume is the same as the moles. hope this helps
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Between which two pints does the object have the greatest speed please help
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The answer is A to B because the distance is rising rapidly as seen by the steep slope segment A to B had
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3 years ago
Least to greatest 2.62,2 2/5, 26.8%, 2.26%,271%
olga_2 [115]
2.26%, 26.8%, 2 2/5, 2.62, 271%

Hope this helps! :D
3 0
3 years ago
Read 2 more answers
Now, examine the structures of benzhydrol and fluorene. Both compounds contain the same number of carbons but have very differen
zubka84 [21]

Answer:

The OH group

Explanation:

Benzhydrol contains OH hydroxyl group in its molecule while fluorene does not. At first glance, one would think that OH, which contributes to hydrogen bonding would causes melting point of benzhydrol to be higher than fluorene. <em>However, </em>the structure of benzhydrol, which is 2 benzene rings connected to center hydroxyl carbon (PhCOHPh), allows for each benzene rings in benzhydrol to rotate until both rings are perpendicular to minimize repulsive force. This prevents the molecule from stacking on each other due to its non flat shape, and thus, lowering its melting point in contrast to flat fluorene molecule.

4 0
3 years ago
1. Suppose the mechanical advantage of a machine is 4, and the input force is 20 N.
Contact [7]

Answer:

80 N

Explanation:

you can multiple

force equal to mass x gravity

3 0
2 years ago
A 0.211 g sample of carbon dioxide, CO2, has a volume of 560 mL and a pressure of 429 mmHg whats the temperature of the gas in K
SCORPION-xisa [38]

The temperature of the gas sample is 813 K.

<u>Explanation:</u>

We have to use the ideal gas equation to find the temperature of the gas sample.

The ideal gas equation is PV = nRT

Pressure, P = 429 mm Hg = 0.56 atm

Volume, V = 560 mL = 0.56 L

R = gas constant = 0.08205 L atm mol⁻¹K⁻¹

Mass = 0.211 g

Molar mass of carbon di oxide = 44.01 g / mol

Moles, n = $\frac{given mass}{molar mass} = \frac{0.211 g}{44.01 g/mol}

              = 0.0047 mol

Now, we have to plugin the above values in the above equation, we will get the temperature as,

$T= \frac{PV}{nR}

T = $\frac{0.56  \times 0.56}{0.08205 \times 0.0047}

 = 813 K

So the temperature of the gas sample is 813 K.

5 0
3 years ago
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