PV=nRT
P= ? atm
V= 2 L
T= 423 K
n= 2.3 moles
R= 0.08205
(P)(2)=(2.3)(0.08205)(423)
P= (79.826445)/(2)
P= 39.9132225 atm
Answer:
C. 40
Explanation:
there are 40 moles of water in a 0.250 mole. use the formula to find out
40.0 = 40.0 + 0
If 28.0 grams of a gas occupies 22.4 liters at STP, the gas could be carbon monoxide, CO
<h3>Ideal gas </h3>
We understood from the ideal gas equation that 1 mole of any gas occupies 22.4 liters at standard temperature and pressure (STP)
<h3>How to determine the identity of the gas</h3>
To determine the identity of the gas, we shall determine the mass of 1 mole of each gas. This can be obtained as
For C₂H₂
1 mole of C₂H₂ = (12×2) + (2×1) = 26 g
For C₂H₆
1 mole of C₂H₆ = (12×2) + (6×1) = 30 g
For CO₂
1 mole of CO₂ = 12 + (16×2) = 44 g
For CO
I mole of CO = 12 + 16 = 28 g
From the above illustrations, we can see that 1 mole of CO is equivalent to 28 g.
Thus, the correct answer to the question is CO
Learn more about ideal gas equation:
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Answer:
The light bulb converts electrical energy into light and <u>heat energy</u>
Answer is: Te (tellurium).
During electron capture, iodine-123 f<span>orm the nearly-stable nuclide tellurium-123.
</span>In beta
plus decay (atomic number Z is decreased by one), a proton is converted to a neutron
and positron and an electron neutrino, so mass <span>number does not
change.
</span>Iodine-123 is a radioactive isotope of iodine used in nuclear medicine imaging.<span>
</span>
