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timurjin [86]
3 years ago
11

calculate the translational partition function of xenon and helium at the them temperature and volume

Chemistry
1 answer:
son4ous [18]3 years ago
4 0

Explanation:

a) The ratio of the translational partition of D2 and H2 is 2.82

b) The ratio of the translational partition of xenon and helium is 187.56

Explanation:

a) The translational partition for D₂ is equal to:

Where

m = mass of molecule

k = Boltzmann constant

T = absolute temperature

V = volume of container

h = Planck constant

If rewrite the equation:

The same for the H₂ molecule:

Taking the ratio D₂ and H₂:

Where

mH₂ = 2.015894 amu

mD₂ = 4.028204 amu

b) The same way to part a)

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Water is flowing in a pipe with a mass flow rate of 100.0 lb/h (M water H,O=18.016). What is the (i) Molar flow rate of H20 (gmo
Arada [10]

Answer:

i) 0,7 molH20/s

ii)11,2 g O/s

iii)1,4 g H/s

Explanation:

i) To find the molar flow rate of water, we just convert the mass of water to moles of water using its molecular weight(g/mol) and changing to the proper units (lb to grames and hours to seconds):

100 \frac{lb}{h}*\frac{453,5g}{1 lb}*\frac{1molH20}{18,016g}*\frac{1h}{3600s}=0,7\frac{molH20}{s}

ii) Now we just consider the oxygen in the water stream (for 1 mole of water there is 1 mole of oxygen):

100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{1molO}{1molH20}*\frac{16gr}{1molO}*\frac{1h}{3600s}=11,2\frac{gO}{s}

iii)Just considering the hydrogen in the stream (for 1 mole of water there is 2 moles of hydrogen):

100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{2molH}{1molH20}*\frac{1gr}{1molH}*\frac{1h}{3600s}=1,4\frac{gH}{s}

3 0
3 years ago
How many liquids are found on the periodic table?<br><br><br><br> 1
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There are six liquids found on the periodic table.

1. Bromine

2. Mercury

3. Caesium

4. Gallium

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3 0
3 years ago
What is the most likely formula for an oxide formed between group a 1 atom x and oxygen
Marizza181 [45]
The most likely formula for an oxide formed between group 1a atom X and oxygen would be

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5 0
3 years ago
If the CaCO3 weighed 983 g and the CaO weighed 551 g, how many grams of CO2 were formed in the reaction?
stira [4]

Answer:

The answer to your question is 432 g of CO₂

Explanation:

Data

CaCO₃  = 983 g

CaO = 551 g

CO₂ = ?

Balanced reaction

                               CaCO₃ (s)   ⇒   CaO (s)   +  CO₂ (g)

This reaction is balanced, to solve this problem just remember the Lavoisier Law of conservation of mass that states that the mass of the reactants is equal to the mass of the products.

                    Mass of reactants = Mass of products

                    Mass of CaCO₃   = Mass of CaO + Mass of CO₂

Solve for CO₂

                    Mass of CO₂  = Mass of CaCO₃ - Mass of CaO                    

                     Mass of CO₂ = 983 g - 551 g

Simplification

                     Mass of CO₂ = 432 g                        

         

5 0
3 years ago
Water is boiled in a flask with a balloon over the top of the water gets the balloon expand what has happened to the weight of t
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It decreases since a air less balloon is heavier than a Aired balloon
7 0
3 years ago
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