A first-order reaction is 81omplete in 264s.The half-life for this reaction (i) t 1/2 = =3.465×10 −3 s.to reach 95% Completion = 285 s.
To measure reaction rates, chemists initiate the reaction, measure the concentration of the reactant or product at different times as the reaction progresses,
For a 0-order response, the mathematical expression that may be employed to determine the half of life is: t1/2 = [R]0/2k. For a first-order reaction, the half of-existence is given by: t1/2 = zero.693/ok. For a 2d-order response, the method for the half-life of the response is: 1/okay[R]0
The 1/2-life of a response (t1/2), is the quantity of time needed for a reactant concentration to lower via half of compared to its initial awareness. Its software is used in chemistry and medicine to are expecting the awareness of a substance over time
Half of the lifestyles is the time required for exactly 1/2 of the entities to decay 50%.
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Answer: The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is 
Explanation:
The combined gas equation is,
where,
= initial pressure of gas = 0.947 atm
= final pressure of gas = 0.987 atm
= initial volume of gas = 150 ml
= final volume of gas = 144 ml
= initial temperature of gas = 
= final temperature of gas = ?
Now put all the given values in the above equation, we get:
The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is
<span> C.The results of the Michelson-Morley experiment did not fit the theory of the luminiferous ether, so the theory had to be rejected. </span>
