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timurjin [86]
3 years ago
11

calculate the translational partition function of xenon and helium at the them temperature and volume

Chemistry
1 answer:
son4ous [18]3 years ago
4 0

Explanation:

a) The ratio of the translational partition of D2 and H2 is 2.82

b) The ratio of the translational partition of xenon and helium is 187.56

Explanation:

a) The translational partition for D₂ is equal to:

Where

m = mass of molecule

k = Boltzmann constant

T = absolute temperature

V = volume of container

h = Planck constant

If rewrite the equation:

The same for the H₂ molecule:

Taking the ratio D₂ and H₂:

Where

mH₂ = 2.015894 amu

mD₂ = 4.028204 amu

b) The same way to part a)

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C3H8+3O2 = 3CO2+4H2O what is the enthalpy combustion
dezoksy [38]

Answer:

\Delta H_{comb}=2043.85kJ/mol

Explanation:

Hello there!

In this case, according to the given chemical reaction, it possible for us to set up the expression for the calculation of the enthalpy change as shown below:

\Delta H_r=-\Delta H_{comb}=3\Delta _fH_{CO_2}+4\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-3\Delta _fH_{O_2}

Thus, given the values of the enthalpies of formation on the attached file, we obtain:-\Delta H_{comb}=3(-393.5kJ/mol)+4(-241.8kJ/mol)-(-103.85kJ/mol)-3(0kJ/mol)\\\\-\Delta H_{comb}=-2043.85kJ/mol\\\\\Delta H_{comb}=2043.85kJ/mol

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2 years ago
Iron sulfide is a compound. It is made by heating a mixture of iron and sulfur.
lara [203]

Answer:

Here are some of the differences between a mixture of iron and sulfur, and iron sulfide: the mixture can contain more or less iron, but iron sulfide always contains equal amounts of iron and sulfur. the iron and sulfur atoms are not joined together in the mixture, but they are joined together in iron sulfide.

Explanation:

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Earth is unique because it is the _____.
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Answer:

B. The only planet to support life.

Explanation:

5 0
3 years ago
Read 2 more answers
HELP PLEASE THE OTHER 'ANSWER' ISNT EVEN AN ANSWER!
hodyreva [135]

Answer:

most likely that (2) the replicated experiment was performed incorrectly.

Why, u ask? u dare question me:

1- The initial experiment invalidness cannot be proven.

2- <em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>s</u></em><em><u>e</u></em><em><u>c</u></em><em><u>o</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u>s</u></em><em><u>w</u></em><em><u>e</u></em><em><u>r</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>c</u></em><em><u>o</u></em><em><u>r</u></em><em><u>r</u></em><em><u>e</u></em><em><u>c</u></em><em><u>t</u></em>

3- Different labaratories does not effect the outcome, as long as the parameter and environment of the replicated experiment is the same as when the initial experiment was conducted.

4- Already knowing the data and errors would increase the precision of the replicated experiment.

5- Change in variables should still be in the objective (or purpose) of the experiment, thus, major difference in the outcome should not happen.

happy learning!

4 0
3 years ago
9. A student wished to prepare ethylene gas by dehydration of ethanol at 140oC using sulfuric acid as the dehydrating agent. A l
Arte-miy333 [17]

We have that the the liquid is

  • C_2H_5OH (ethanol
  • And at a condition of H_2SO4 as catalyst and temp 170

From the question we are told

  • A student wished to prepare <em>ethylene </em>gas by <em>dehydration </em>of ethanol at 140oC using sulfuric acid as the <em>dehydrating </em>agent.
  • A low-boiling liquid was obtained instead of ethylene.
  • What was the liquid, and how might the reaction conditions be changed to give ethylene

<h3>Ethylene formation</h3>

Generally the equation is

2C_2H_5OH------CH3CH_2O-CH_2CH_3+H_20

Therefore

with ethanol at 140oC

The product is diethyl ethen

The reaction at 170 ethylene will give

C_2H_5OH-------CH_2=CH_2+H_2O( at a condition of H_2SO4 as catalyst and temp 170)

Therefore

The the liquid is

  • C_2H_5OH (ethanol

For more information on Ethylene visit

brainly.com/question/20117360

8 0
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