<u>Answer:</u> The freezing point of solution is -10.9°C and the boiling point of solution is 103.°C
<u>Explanation:</u>
To calculate the mass of water, we use the equation:
Density of water = 1 g/mL
Volume of water = 129 mL
Putting values in above equation, we get:
Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.
- The equation used to calculate depression in freezing point follows:
To calculate the depression in freezing point, we use the equation:
Or,
where,
Freezing point of pure solution = 0°C
i = Vant hoff factor = 2 (For NaCl)
= molal freezing point elevation constant = 1.86°C/m
= Given mass of solute (NaCl) = 22.1 g
= Molar mass of solute (NaCl) = 58.5 g/mol
= Mass of solvent (water) = 129 g
Putting values in above equation, we get:
Elevation in boiling point is defined as the difference in the boiling point of solution and boiling point of pure solution.
- The equation used to calculate elevation in boiling point follows:
To calculate the elevation in boiling point, we use the equation:
Or,
where,
Boiling point of pure solution = 100°C
i = Vant hoff factor = 2 (For NaCl)
= molal boiling point elevation constant = 0.512°C/m
= Given mass of solute (NaCl) = 22.1 g
= Molar mass of solute (NaCl) = 58.5 g/mol
= Mass of solvent (water) = 129 g
Putting values in above equation, we get:
Hence, the freezing point of solution is -10.9°C and the boiling point of solution is 103.°C