Answer:Please include images of the graphs!
What you want to do is cross multiply so you get 5(x+4)=7(3x+28) then you distrubute the 5 and then you distribute the 5 and the 7 to the number in the parentheses 5x+20=21x+196
subtract 5x on both sides to get 20=16x+196 then you subtract 196 on both sides to get -176=16x last what you want to do is divide 16 on both sides to get x=-11
Answer: x = 2 and y = -4
x + 2y = -6
x = -6-2y
Putting this in value of x in
6x + 2y = 4
6(-6-2y) + 2y = 4
-36-12y+2y = 4
-10y = 4+36
y = 40/(-10)
y = -4
Now putting this value of y in
x + 2y = -6
x + 2(-4) = -6
x -8 = -6
x = -6+8
x = 2
Therefore x = 2 and y = -4
If we put these values we can check this
x + 2y = -6
2 + 2(-4) = -6
2 -8 = -6
-6 = -6
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Given:
The height h of an object after t seconds is

The height of a neighboring 50-foot tall building is modeled by the equation h=50.
The time (t) when the object will be at the same height as the building is found to be t = –2 and t = 5.
To find:
The statement which describes the validity of these solutions.
Solution:
We have,

Here, t is the time in seconds.
For t=-2,



For t=5,



So, the value of h is 50 at t=-2 and t=5.
We know that time is always positive so it cannot be negative value. It means t=-2 is not possible.
The solution t = 5 is the only valid solution to this system since time cannot be negative.
Therefore, the correct option is C.
15x^2 = 12x
divide each side by x
15x = 12
now divide each side by 15
x = 12/15 or 4/5 which is also 0.8