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4 years ago

Gets Brainliest and 11pts!

Mathematics

1 answer:

belka [17]4 years ago

7 0

Volume sphere A V1 = (4/3)πR³

R=∛((3/4)V1/π)

Volume sphere B V2= (4/3)πr³

r=∛((3/4)V2/π)

R-r = ∛((3/4)40/π) - ∛((3/4)10/π) ≈ 0.8 inch

Answer C. 0.8 inch.

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Defiantly need help with this one please HELP AND EXPLAIN

slega [8]

12 miles in 48 minutes
12/48 or 1/4 miles per minute
Times 60 is 15 miles per hour

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3 years ago

Read 2 more answers

A clothing store has the sign shown in the shop window.

kicyunya [14]

Pani would pay $59 if she gets a discount of $3 on each shirt and $3 on each jeans

Step-by-step explanation:

Given

Price of shirt = $12

Price of jeans = $19

Price of shirt after $3 discount = 12-3 = $9

Price of jeans after 3 discount = 19-3 = $16

The total money Pani has to pay will be:

$9(3)+16(2)\\=27+32\\=\$59$

Pani would pay $59 if she gets a discount of $3 on each shirt and $3 on each jeans

Keywords: Discount, percent

Learn more about discount at:

#LearnwithBrainly

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3 years ago

List the first 3 common multiples of 2 and 3 , 3 and 6

musickatia [10]

The smallest 3 common multiples of 2 and 3 are 6, 12, and 18 .

The smallest 3 common multiples of 3 and 6 are also 6, 12, and 18 .

7 0

3 years ago

Read 2 more answers

andy constructed a triangle angle 1 and 2 are the same but angle 3 has a measurement of 100 degrees what is the measurement of a

attashe74 [19]

The triangle has one angle of 100 degrees, and the other two are equal.
We know that the angles of a triangle always add up to 180. To find the measurement of angle 1 and 2, let's solve for this equation.
2x + 100 = 180, where x=angle 1 = angle 2. Subtract 100 from both sides
2x = 80 Divide both sides by 2
x = 40

5 0

3 years ago

3.11 A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the nu

djverab [1.8K]

Answer:

Probability distribution for x:

$P(x=0)=0.3644\\\\P(x=1)=0.4373\\\\P(x=2)=0.1749\\\\P(x=3)=0.0233\\\\$

Step-by-step explanation:

We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.

The probability of k defective sets in the group is:

$P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}$

So, we have this probabilty distribution for x:

$P(x=0) = \dbinom{3}{0} p^{0}q^{3}=1*1*0.3644=0.3644\\\\\\P(x=1) = \dbinom{3}{1} p^{1}q^{2}=3*0.2857*0.5102=0.4373\\\\\\P(x=2) = \dbinom{3}{2} p^{2}q^{1}=3*0.0816*0.7143=0.1749\\\\\\P(x=3) = \dbinom{3}{3} p^{3}q^{0}=1*0.0233*1=0.0233\\\\\\$

7 0

3 years ago