1 is b 2 is a 3 is d 4 is a 5 is c
Answer:
<u>= 2.2 g pf S. produced</u>
Explanation:
Balanced Reaction equation:
→ 
1 mole of H2S - 34.1g
? moles - 3.2g
= 3.2/34.1 =<u> 0.09 moles of H2S</u>
Also,
1 mole of S02 - 64.07 g
? moles - 4.42g
= 4.42/64.07 <u>= 0.069 moles of SO2</u>
<u />
<em>Meaning SO2 is the limiting reagent</em>
Finally, 3 moles of S - 32g of sulphur
0.069 mole = ? g of Sulphur
= 0.069 x 32
<u>= 2.2 g pf S.</u>
Answer:
x-10 should be the answer
Answer: 1) 
Equilibrium constant is defined as the ratio of the product of concentration of products to the product of concentration of reactants each term raised to their stochiometric coefficients.
![K_{eq}=\frac{[H_2S]^2}{H_2]^2\times [S_2]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BH_2S%5D%5E2%7D%7BH_2%5D%5E2%5Ctimes%20%5BS_2%5D%7D)
where [] = concentration in Molarity=
Thus ![[H_2S]=\frac{68.5}{1.0}=68.5M](https://tex.z-dn.net/?f=%5BH_2S%5D%3D%5Cfrac%7B68.5%7D%7B1.0%7D%3D68.5M)
![[H_2]=\frac{0.50}{1.0}=0.50M](https://tex.z-dn.net/?f=%5BH_2%5D%3D%5Cfrac%7B0.50%7D%7B1.0%7D%3D0.50M)
![[S_2]=\frac{0.020}{1.0}=0.020M](https://tex.z-dn.net/?f=%5BS_2%5D%3D%5Cfrac%7B0.020%7D%7B1.0%7D%3D0.020M)
![K_{eq}=\frac{[68.5]^2}{0.50]^2\times [0.020]}=938450](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5B68.5%5D%5E2%7D%7B0.50%5D%5E2%5Ctimes%20%5B0.020%5D%7D%3D938450)
As the value of K is greater than 1, the reaction is product favored.
2) 
![K_{eq}=\frac{[NO_2]^2}{[N_2O_4]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BN_2O_4%5D%7D)
![K_{eq}=\frac{[0.500]^2}{[0.0250]}=10](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5B0.500%5D%5E2%7D%7B%5B0.0250%5D%7D%3D10)
3) 
![K_{eq}=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5Ctimes%20%5BH_2%5D%5E3%7D)
4) Reactions which do not continue to completion are called equilibrium reactions as the rate of forward reaction is equal to the rate of backward direction.
Chemical reaction of PO₄³⁻ ion in water:
PO₄³⁻(aq) + H₂O(l) → HPO₄²⁻(aq) +OH⁻(aq).
Kb = [HPO₄²⁻] · [OH⁻] / [PO₄³⁻]; <span>base ionization constant.
</span>Base ionization constant <span>is the equilibrium </span>constant<span> for the </span>ionization<span> of a </span>base<span>.
</span>According
to Bronsted-Lowry theory acid are donor of protons and bases are
acceptors of protons (the hydrogen cation or H⁺<span>).
</span>PO₄³⁻ is Bronsted base and it can accept proton and
become conjugate acid HPO₄²⁻.