Answer:
Explanation:
1 mol of anything is 6.02 * 10^23 atoms (in this case)
x mol of 3.01 * 10^22
Set up the proportion
1/x = 6.02*10^23 / 3.01 * 10^22 Cross multiply
x*6.02 * 10^23 = 1 * 3.01 * 10^22 Divide by 6.02*10^23
x = 3.01 * 10^22 / 6.02*10^23
x = 1/(2 * 10)
x = 1/20 mol
x = 0.05 mol
Cooled in ice to help the water vapour condense. Tube 2 – contains lime water, goes cloudy to show the presence of carbon dioxide. Word equation: (hydrocarbon + oxygen → carbon dioxide + water) Methane + oxygen → carbon dioxide + water.
In this drama, a crucible would represent the constant building action leading to the climax of the pot.
What is crucible?
A crucible is a ceramic as well as metal vessel used to melt metals or subject other substances to extremely high temperatures. Crucibles can be made from any material that can withstand temperatures high enough to melt and otherwise change their contents, despite historically being most frequently made of clay. The crucible's shape has changed over time, with designs that take into account both regional variation and the process for that they are used. The earliest crucible forms date to Iran and Eastern Europe in the sixth or fifth millennia B.C.
Similar to the contents of a crucible, the characters seem to be constantly enduring severe trials; in this case, the witching trials. The crucible would, in my opinion, symbolize the town itself and its residents. The symbolism of this suggests a theme of the townspeople going through the witching trials and coming out with a "refined" lesson. The unnecessary accusations and trials will teach a hard lesson to the people who live within the town and influence their future.
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For an aqueous solution of MgBr2, a freezing point depression occurs due to the rules of colligative properties. Since MgBr2 is an ionic compound, it acts a strong electrolyte; thus, dissociating completely in an aqueous solution. For the equation:
ΔTf<span> = (K</span>f)(<span>m)(i)
</span>where:
ΔTf = change in freezing point = (Ti - Tf)
Ti = freezing point of pure water = 0 celsius
Tf = freezing point of water with solute = ?
Kf = freezing point depression constant = 1.86 celsius-kg/mole (for water)
m = molality of solution (mol solute/kg solvent) = ?
i = ions in solution = 3
Computing for molality:
Molar mass of MgBr2 = 184.113 g/mol
m = 10.5g MgBr2 / 184.113/ 0.2 kg water = 0.285 mol/kg
For the problem,
ΔTf = (Kf)(m)(i) = 1.86(0.285)(3) = 1.59 = Ti - Tf = 0 - Tf
Tf = -1.59 celsius
