Question

A line is perpendicular to y=x/3-2 and passes through point( 6,2) write its equation

Answer 1

First find slope of perpendicular:

M=1/3, so new slope m= -3

y=mx + b, and subsitute (6,2) and m

2=-3(6) + b, move -18 to other side

b=20

y = -3x+20