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Greeley [361]
3 years ago
13

A line is perpendicular to y=x/3-2 and passes through point( 6,2) write its equation

Mathematics
1 answer:
Katarina [22]3 years ago
6 0

First find slope of perpendicular:

M=1/3, so new slope m= -3

y=mx + b, and subsitute (6,2) and m

2=-3(6) + b, move -18 to other side

b=20

y = -3x+20

You might be interested in
I beg help me finish this HW
erastovalidia [21]

Answer: The mixed number 16 1/3

Some books write this as 16 & 1/3 to help separate out the whole part (16) and the fractional part (1/3) better.

On paper, you'd write it as 16 \frac{1}{3}

===========================================================

Explanation:

The three angles mentioned (AOC, DOC, EOD) all combine to form a straight angle AOD = 180 degrees

So we can say,

(angle AOC) + (angle DOC) + (angle EOD) = angle AOD

(angle AOC) + (angle DOC) + (angle EOD) = 180

(7x-2) + (2x+8) + (27) = 180

7x-2 + 2x+8 + 27 = 180

(7x+2x) + (-2+8+27) = 180

9x+33 = 180

9x = 180-33 ... subtract 33 from both sides

9x = 147

x = 147/9 .... divide both sides by 9

x = 16.333333 .... use calculator here

The stuff to the left of the decimal (16) is the whole part

The decimal part 0.33333 where the 3's go on forever converts to 1/3

We can see this if we multiply 0.33333 with 9 getting 0.33333*9 = 2.99997

and that rounds to 3, so 3/9 = 1/3

In short, 16.333333 = 16 & 1/3

3 0
4 years ago
Suppose we want to choose 2 colors, without replacement from 3 colors red blue and green how many ways can this be done in the o
andre [41]

The two colors can be chosen in 3 different ways.

<h3>In how many ways can we choose two colors?</h3>

If we have a set of N elements, the number of different sets of K elements (such that the order of the K elements does not matter) is:

C(N, K) = \frac{N!}{(N - K)!*K!}

In this case, we have 3 colors, so N=3, and we want to choose 2, then K=2.

Replacing that we get:

C(3, 2) = \frac{3!}{(3- 2)!*2!} = \frac{3*2*1}{1*2*1}  = 3

The two colors can be chosen in 3 different ways.

If you want to learn more about combinations:

brainly.com/question/11732255

#SPJ1

3 0
2 years ago
Which of these can not form a perpendicular bisector?
sdas [7]
B. Is the correct answer. A circle can not form a perpendicular bisector as it is rounded and not straight.
4 0
3 years ago
Read 2 more answers
(-2ab+6a-6)-(-4ab-6)
AVprozaik [17]
(-2ab + 6a - 6 ) - (-4ab - 6)=   ***at this step you have to distribute the negative sign 

=-2ab + 6a - 6 +4ab + 6

= 2ab + 6a

hope this helps

3 0
4 years ago
Read 2 more answers
Which equation is not equvilant to A=1/2 bh,
ollegr [7]
Which equation is not equvilant It is c
3 0
4 years ago
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