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Vlad [161]
2 years ago
10

If it takes 43.32 mL of 0.1 M NaOH to neutralize a 50 mL HCl solution, what is the molarity of HCI?

Chemistry
1 answer:
Strike441 [17]2 years ago
7 0

FOLLOW ME FOR CLEARING YOUR NEXT DOUBT

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What career is when a person anlysis food in laboratory ?
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Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide. Ca) + H2O --> Ca(OH)2 In a particular
mars1129 [50]

Answer:

Percent yield = 92.5%

Explanation:

The question asks for the percent yield which can be defined as:

\frac{actual yield}{theoretical yield} .100

Where the actual yield is <em>how much product was obtained</em>, in this case 6.11 g of Ca(OH)₂, and the theoretical yield is <em>how much product could be obtained with the given reactants theoretically</em>, that is if the reaction would work perfectly. So we need to calculate first the theoretical yield.

1. First lets write the chemical equation reaction correctly and check that it is balanced:

CaO + H₂O → Ca(OH)₂

2. Calculate the amount of product Ca(OH)₂ that can be obtained with the given reactants (theoretical yield), which are 5.00g of CaO and excess of water. So the amount of CaO will determined how much Ca(OH)₂ we can obtained.

For this we'll use the molar ratio between CaO and Ca(OH)₂ which we see it is 1:1. For every mol of CaO we'll obtain a mol of Ca(OH)₂. So lets convert the 5.00 g of CaO to moles:

 Molar Mass of CaO: 40.078 + 15.999 = 56.077 g/mol

 moles of CaO = 5.00 g / 56.077 g/mol = 0.08916 moles

As we said before from the molar ratio moles of Ca(OH)₂ = moles of CaO

So the moles of Ca(OH)₂ that can be obtained are 56.077 g/mol

We need to convert this value to grams:

 Molar Mass of Ca(OH)₂ = 40.078 + (15.999 + 1.008)*2 = 74.092 g/mol

Theoretical yield of Ca(OH)₂ = 0.08916 moles x 74.092 g/mol = 6.606 g

3. Calculate the percent yield:

\frac{actual yield}{theoretical yield} .100

Percent yield = (6.11 g / 6.606g) x 100 = 92.5 %

5 0
3 years ago
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How many valence electrons can atoms of non metals have?
Dmitry_Shevchenko [17]

1 to 8 valence electrons

7 0
3 years ago
A piece of copper has a volume 130 L. What is the mass of the sample, in units of kilograms?
Reil [10]

Answer: The mass of the sample is 1264.800 kg.

Explanation:

Mass of the piece of copper = m

Volume of the copper price = 130 L=130,000 cm^3

1 L= 1,000 cm^3

Density=8.96 g/cm^3=\frac{Mass}{Volume}=\frac{Mass}{130,000 cm^3}

m=Density\times Volume=8.96 g/cm^3\times 130,000=1,264,800 g

m = 1,264,800 g = 1,264.800 kg (1 kg = 1000 g)

The mass of the sample is 1264.800 kg.

3 0
3 years ago
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