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Vlad [161]
3 years ago
10

If it takes 43.32 mL of 0.1 M NaOH to neutralize a 50 mL HCl solution, what is the molarity of HCI?

Chemistry
1 answer:
Strike441 [17]3 years ago
7 0

FOLLOW ME FOR CLEARING YOUR NEXT DOUBT

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CORRECT ANSWER GETS BRAINEST!!! <br><br> Which element is in Group 6, Period 4? (Look at image)
vaieri [72.5K]

Answer:

Se

Explanation:

Se is in geoup 6, period 4

7 0
3 years ago
Read 2 more answers
A scientist thinks she has discovered a new element. She took some samples to her colleagues and they performed some tests. Here
nirvana33 [79]

Answer:

<em><u>Proton number of the supposed discovery debunked the theory.</u></em>

Explanation:

Proton number of an element is also its atomic number.

For the element in question to have had a proton number that wasn't 119, it could not have been a new element.

Furthermore, the characteristics described (proton number especially) describe exactly the Germanium element.

I believe this was helpful.

6 0
3 years ago
How many moles of water molecules are found in 3.80 moles of zinc(ii) sulfate heptahydrate?
Sindrei [870]
Zinc (ii) sulfate heptahydrate has a formula of ZnSO4.7H2O 
Therefore, note that one mole of ZnSO4.7H2O, contains 7 moles of H2O,
Hence, 3.8 moles of ZnSO4.7H2O will contain;
   3.8 × 7/1
  = 26.6 moles of H2O
3 0
4 years ago
State two differences between an element and a compound.​
Umnica [9.8K]

Answer:

See the picture... I hope that's the answer

7 0
3 years ago
A pure radioactive substance has a mass of 30 micrograms but had a mass of 240 micrograms 48 years ago. Assuming that the only c
defon

Answer: Half-life of the substance is 16 years.

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  

t = age of sample  = 48 years

a = initial amount of the reactant = 240 micrograms

a - x = amount left after decay process = 30 microgarms

48=\frac{2.303}{k}\log\frac{240}{30}

k=\frac{2.303}{48}\log\frac{240}{30}

k=0.0433years^{-1}

b) t_{\frac{1}{2}} of reaction  

t_{\frac{1}{2}}=\frac{0.693}{k}=\frac{0.693}{0.0433}=16years

Thus half-life of the substance is 16 years.

7 0
3 years ago
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