Acid-base tiltrations has DNA that can help in the process of neutralization. not so sure about it
Answer:
evaporation.
evaporation is the process by which water changes from liquid to a gas or vapor.
I'm not sure how many sign fig's you are required to have.
However I think the final answer would be 0.05 Moles, because of the .5g, that is considered 1 sign fig.
Answer : The vapor pressure of bromine at
is 0.1448 atm.
Explanation :
The Clausius- Clapeyron equation is :

where,
= vapor pressure of bromine at
= ?
= vapor pressure of propane at normal boiling point = 1 atm
= temperature of propane = 
= normal boiling point of bromine = 
= heat of vaporization = 30.91 kJ/mole = 30910 J/mole
R = universal constant = 8.314 J/K.mole
Now put all the given values in the above formula, we get:


Hence, the vapor pressure of bromine at
is 0.1448 atm.