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katen-ka-za [31]
3 years ago
12

Can someone answer this.

Mathematics
1 answer:
aleksklad [387]3 years ago
5 0

Answer:

1 is the answer I think I am not sure about it just try

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Evaluate:<br> Σ10, 8(27-1) =
vfiekz [6]

Answer:

Step-by-step explanation:

7 0
3 years ago
The volume V (in cubic feet) of a right cylinder with a height of 3 feet and radius r (in feet) is given by V=3πr2. Solve the fo
Kitty [74]

Answer:

r=\sqrt{\frac{V}{3\pi}}\\\\r\approx 5.00\ ft

Step-by-step explanation:

-The volume of a cylinder is given by the formula:

V=3\pi r^2

#We make r the subject of the formula:

V=3\pi r^2\\\\r^2=\frac{V}{3\pi}\\\\r=\sqrt{\frac{V}{3\pi}}

#We then substitute for the stated volume and solve for r:

r=\sqrt{\frac{V}{3\pi}}, V=236\\\\\therefore r=r=\sqrt{\frac{236}{3\pi}}\\\\r=5.00404\approx\ 5.00\ ft

Hence, the cylinder's radius is approximately 5.00 ft

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3 years ago
Plz answer im desperate thank you!
Law Incorporation [45]
The answer is 4 hope this helps
6 0
3 years ago
Read 2 more answers
How you save 6x-2=5x+29
dolphi86 [110]
6x-2=5x+29
6x-5x-2=29
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3 0
2 years ago
According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0
3 years ago
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