Well, as far as I can tell, the mean (average) is the best representation of the data because there is no outlier (a number a lot higher or lower than the rest of the numbers that throws the data off).
Sorry I don't know but i bet more can exolain.
When you roll two numbers you have four kinds of outcomes: EE, EO, OE, OO (where E = even, O = odd).
You get an even sum only if you sum two numbers that are both even or both odd, therefore the outcomes wanted are two: EE and OO.
Therefore:
P(sum is even) = 2 / 4 = 0.5
Hence, there is a 50% probability that, when you roll two numbers, their sum will be even.
Answer:
$50.08
Step-by-step explanation:
Let's use x to represent the lesser expensive hat and 2x to represent the more expensive hat since the more expensive hat is twice the price.
So, our equation would be 2x + x = 75.12
We can combine them together to make 3x.
Then, we make the 3x equal to 75.12
3x = 75.12
Now, we solve it.
Divide both sides by 3 to solve for x.
75.12/3 = 25.04
x = 25.04
Lastly, plug it in for 2x to get the price of the more expensive hat.
2(25.04) = ?
2(25.04) = 50.08
Therefore, the price of the more expensive hat is $50.08
1.59, 1.95, 9.15, 9.5, 15.9
