10(y+2)-y=2(9y-8) i need to know how to solve it
1 answer:
10(y+2)-y=2(9y-8)
Mutiply the first bracket by 10
Mutiply the second bracket by 2
(10)(y)(10)(2)= 10y+20
(2)(9y)(2)(-8)= 18y-16
10y+20-y= 18y-16
10y-y+20= 18y-16
9y+20= 18y-16
move 18y to the other side
sign changes from +18y to -18y
9y-18y+20= 18y-18y-16
-9y+20= -16
move +20 to the other side
sign changes from +20 to -20
-9y+20-20=-16-20
-9y= -36
divide by -9
-9y/-9= -36/-9
y= 4
Answer: y= 4
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