Question

What is the length of the given segments EF and GH?

Answer 1

Answer:

$EF = 5$

$GH = 5$

Step-by-step explanation:

Length of EFis the distance between E(-4, -3) and F (-1, 1).

$EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$E(-4, -3) = (x_1, y_1)$

$F(-1, 1) = (x_2, y_2)$

$EF = \sqrt{(-1 -(-4))^2 + (1 -(-3))^2}$

$EF = \sqrt{(3)^2 + (4)^2}$

$EF = \sqrt{9 + 16} = \sqrt{25}$

$EF = 5$

Distance between G(-2, -3) and H(3, -3)

$GH = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$G(-2, -3) = (x_1, y_1)$

$H(3, -3) = (x_2, y_2)$

$GH = \sqrt{(3 -(-2))^2 + (-3 -(-3))^2}$

$GH = \sqrt{(5)^2 + (0)^2}$

$GH = \sqrt{25 + 0} = \sqrt{25}$

$GH = 5$