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ki77a [65]
3 years ago
12

Messaging systems range from semi-public systems such as standard text messaging on mobile phones, to private systems that are c

losed to anyone outside of invited members.
A. True
B. False
Business
1 answer:
Taya2010 [7]3 years ago
7 0

Answer:

True.

Explanation:

Messaging systems range from semi-public systems such as standard text messaging on mobile phones, to private systems that are closed to anyone outside of invited members.

A messaging system can be defined as an electronic device which enables users to send text messages to one or more users depending on the configuration and it ranges from semi-public systems to private systems.

In a semi-public messaging system, messages can be sent between users with little or no restriction to who can send or receive these messages. An example is sending short standard text on mobile phones.

On the other hand, a private messaging system is a type of system that denies access to individuals outside of the group, only invited members are able to send and receive messages.

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Answer:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

n(1-\hat p) = 25*(1-0.52) =12 \geq 10

So then we satisfy this condition

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So then the answer for this case would be:

a. Yes.

Explanation:

For this case we assume that the question is: If in the experiment described we can use the normal approximation for the proportion of interest.

For this case we have a sample of n =25

And we are interested in the proportion of registered students that spend more than 20 minutes to get to school.

X = 13 represent the number of students in the sample selected that have a time more than 20 min.

And then the estimated proportion of interest would be:

\hat p = \frac{X}{n}= \frac{13}{25}= 0.52

And we want to check if we can use the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So in order to do this approximation we need to satisfy some conditions listed below:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

n(1-\hat p) = 25*(1-0.52) =12 \geq 10

So then we satisfy this condition:

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So then the answer for this case would be:

a. Yes.

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Given that the contract specified a delivery date of March 1.

The equipment was not delivered until March 31 and as such, the revenue for the contract should be recognized on March 31 after the delivery of the equipment.

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