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Dahasolnce [82]
3 years ago
5

Your cousin is moving into an apartment in San Francisco. This apartment is on a street that is angled at 25∘ above the horizont

al. He places a box of mass 15kg on the street. The coefficients of friction between the box and the street are μs=0.45 and μk=0.25.
A: He releases the box after he places it on the ground. Will it start to slide down the sloped road?
Yes or No?
B: As the box slides down the slope, what is its acceleration?
C: What is the magnitude of the minimum force he would have to apply to the box to keep it from sliding down the hill? Assume that he pushes parallel to the road and wants to hold it in place.
D: What is the magnitude of the minimum force he would have to apply to start pushing the box up the hill? Again assume that he pushes parallel to the road.
Physics
1 answer:
Vesnalui [34]3 years ago
5 0

Answer:

70

Explanation:

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Fantom [35]

Answer:

where are the statements so i can see which one is correct

Explanation:

4 0
3 years ago
The part of the electromagnetic spectrum you can see is called ultraviolet light. Please select the best answer from the choices
Artyom0805 [142]
True because when the light bounces off a surface it creates a rainbow which we call roygbiv
4 0
3 years ago
You need to make a spring scale to measure the mass of objects hung from it. You want each 2.1 cm length along the scale to corr
Gennadij [26K]

Answer:

46.67 N/m

Explanation:

mass, m = 0.1 kg

distance, y = 2.1 cm = 0.021 m

Let K be the spring constant.

F = mg = Ky

0.1 x 9.8 = K x 0.021

K = 46.67 N/m

Thus, the spring constant of the spring is 46.67 N/m.

4 0
3 years ago
Read 2 more answers
Two identical sticky masses m are moving in the xy-plane, with their momenta at an angle of φ with one another. They are each mo
postnew [5]

Answer:

ucosφ=-v2cosθ2\\\\φ=cos^{-1} (\frac{-v2cosθ2}{cosφ} )

Explanation:

Two identical sticky masses m are moving in the xy-plane, with their momenta at an angle of φ with one another. They are each moving at the same speed v when they collide at the origin of the coordinates and stick together. After the collision, the masses move at an angle −θ2 with respect to the +x axis at speed v2 .1. What was the angle φ?

from the principle of momentum

In a system of colliding bodies,we know that the total momentum before collision will equal to the total momentum after collision.

Take note that momentum is the product of mass and velocity

momentum before collision=momentum after collision

mass, m

u=initial velocity of the identical masses

v2=the common velocity after the collision

Note that the collision is inelastic , since they both moved with the same velocity

umcosφ+umcosφ=(m+m)v2cos−θ2

2mucosφ=2mv2cos−θ2

ucosφ=-v2cosθ2\\\\φ=cos^{-1} (\frac{-v2cosθ2}{cosφ} )

8 0
3 years ago
You are driving home from school steadily at 95.0 km/h for 130 km. It then begins to rain and you slow to 65.0 km/h. You arrive
harkovskaia [24]
Very simple,Its all about calculating distance using the formula:
D = V x T
where,
V is the speed or velocity
D is distance
T is the time
In the given problem,there are two parts.
Lets do the calculations for both parts separately:
Part 1) Before the rain
Time = 130/95
         = 1.37 hours <span> </span>
<span>Time taken after the rain = Total time - time taken before the rain  </span>
<span>                                        = 3.34 hours - 1.37 hours
                                        = 1.97 hours </span>
<span>Distance covered after the rain = 1.97 hours x 65 km/h
                                                  = 128 km</span>
Hence,
<span>a) The total distance covered =  130 + 128
                                           = 258 km
</span><span>b) Average speed = Total distance/Total time
                             =  260/3.34
                             = 78 km/h </span>
4 0
3 years ago
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