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Dahasolnce [82]
3 years ago
5

Your cousin is moving into an apartment in San Francisco. This apartment is on a street that is angled at 25∘ above the horizont

al. He places a box of mass 15kg on the street. The coefficients of friction between the box and the street are μs=0.45 and μk=0.25.
A: He releases the box after he places it on the ground. Will it start to slide down the sloped road?
Yes or No?
B: As the box slides down the slope, what is its acceleration?
C: What is the magnitude of the minimum force he would have to apply to the box to keep it from sliding down the hill? Assume that he pushes parallel to the road and wants to hold it in place.
D: What is the magnitude of the minimum force he would have to apply to start pushing the box up the hill? Again assume that he pushes parallel to the road.
Physics
1 answer:
Vesnalui [34]3 years ago
5 0

Answer:

70

Explanation:

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The droplets on a glass of ice water are a result of water vapor releasing energy and changing to water droplets.
olya-2409 [2.1K]

Answer:

B. condensation

Explanation:

hope this helps

4 0
3 years ago
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How much energy (in Joules) is released when 12.0 g of water cools from 20.0 °C to 11.0 °C? This is a grade 10 question from the
KATRIN_1 [288]

Answer: - 452.088joule

Explanation:

Given the following :

Mass of water = 12g

Change in temperature(Dt) = (11 - 20)°C = - 9°C

Specific heats capacity of water(c) = 4.186j/g°C

Q = mcDt

Where Q = quantity of heat

Q = 12g × 4.186j/g°C × - 9°C

Q = - 452.088joule

7 0
3 years ago
Two projectile launchers are beside one another on level ground. Both launchers are directed at the same angle with respect to g
kakasveta [241]

Answer:

(a) Projectile B will travel 4 times as far as projectile A prior to landing

Explanation:

Initial velocity = v

Angle at which the projectile is shot at = θ

g = Acceleration due to gravity

Range of a projectile is given by

R=\frac {v^{2}\sin 2\theta}{g}

When Initial velocity = v

R_A=\frac{v^{2}\sin 2\theta}{g}

When Initial velocity = 2v

R_B=\frac{(2v)^{2}\sin 2\theta}{g}\\\Rightarrow R_B=\frac{4v^2\sin 2\theta}{g}

Dividing the equtions, we get

\frac{R_A}{R_B}=\frac{\frac{v^{2}\sin 2\theta}{g}}{\frac{4v^2\sin 2\theta}{g}}

Here, the angle at which the projectiles are fired at are equal.

\frac{R_A}{R_B}=\frac{1}{4}\\\Rightarrow R_B=4R_A

Hence, projectile B will travel 4 times as far as projectile A prior to landing

7 0
3 years ago
Objects appear different in size and shape in a container of water due to
o-na [289]

Answer:

A. refraction of light waves

Explanation:

Refraction happens when light travels from one medium to another and changes speed and bends. This also causes objects to look different sizes and shapes when they are submerged in water.

5 0
3 years ago
How does the nuclear charge relate to the energy of the 1s orbital?
nlexa [21]

Explanation:

Effective nuclear charge is defined as he net positive charge experienced by an electron in an atom. It is termed "effective" because the shielding effect of electrons prevents higher orbital electrons from experiencing the full nuclear charge of the nucleus due to the repelling effect of inner-layer electrons.

The 1s is the closest shell to the nucleus of an therefore maximum nuclear charge is experienced. The formula for effective nuclear charge is:

Zeff = Z – S

where

Z = the number of protons in the nucleus, and

S = the shielding constant, the average number of electrons between the nucleus and the electron.

Hence, the energy required to remove an electron from the 1s orbital is the strongest.

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4 years ago
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