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bulgar [2K]
3 years ago
5

Calculate the speed of an object that moves 200 m in 4 s?

Physics
1 answer:
Rasek [7]3 years ago
7 0
50m/s

I divided the 200m by 4s (so 200/4) to get 50m per second
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An object moves from position +34m to the position -15m in 15 seconds. What is the total displacement? What is the total velocit
Alexandra [31]

1) Displacement: -49 m, in the negative direction

Explanation:

The displacement of an object is a vector, whose magnitude is given by the difference between the final point of the motion and the starting point:

d=p_f -p_i

In this problem, the starting point is +34 m, while the final position is -15 m; therefore, the displacement is:

d=-15 m- (+34 m)=-49 m

and the direction is negative, in according to the negative sign.


2) Velocity: -3.27 m/s

Explanation:

Velocity is equal to the ratio between the displacement and the time taken:

v=\frac{d}{t}

in this problem, we have:

d = -49 m is the displacement

t = 15 s is the time

therefore, the velocity is

v=\frac{-49 m}{15 s}=-3.27 m/s

and the direction is negative.

8 0
3 years ago
PHYSICS. <br> ……………………………………………….
belka [17]

Answer:

Work, W = F * d, and

Work = change in kinetic energy, so W=deltaKE.

Hence,

deltaKE=F * d

(1/2)*m*v^2 =F * d

d=[(1/2)*m*v^2]/F

d=[(1/2)*0.6*20^2]/5

d=24 m.

Explanation:

Work = change in kinetic energy, so W=deltaKE.

5 0
2 years ago
I need some help help
Semmy [17]
I believe it’s B but I suggest u chec
4 0
3 years ago
Read 2 more answers
You have 2 resistors of unknown values you label Ra and Rb. You have an old battery and a multimeter you bought years ago for 7$
Veseljchak [2.6K]

Answer:

the answers, the correct one is D,   Rb₂ = 29.97 ohm

Explanation:

For this exercise we use ohm's law and the equivalent resistance ratio for series and parallel circuits.

Serial circuit

         (Ra + Rb) is = V

         (Ra + Rb) 0.111 = 10

         (Ra + Rb) = 10 / 0.111 = 90.09

parallel circuit

         \frac{1}{R} = \frac{1}{Ra} + \frac{1}{Rb}

           R = \frac{Ra \ Rb}{Ra + Rb}

          \frac{Ra \ Rb}{Ra + Rb} i_p = V

         \frac{Ra \ Rb}{Ra + Rb} 0.5 = 10

         \frac{Ra \ Rb}{Ra + Rb} = 10 / 0.5 = 20

we write and solve our system of equations

         Ra + Rb = 90.09

         \frac{Ra \ Rb}{Ra + Rb} = 20

         

we solve for Ra in the first equation

          Ra = 90.09 - Rb

           RaRb = 20 (Ra + Rb)

we substitute Ra in the second equation

           (90.09-Rb) Rb = 20 [(90.09-Rb) + Rb]

            90.09 Rb - Rb² = 20 90.09

           

            Rb² - 90.09 Rb + 1801.8 = 0

we solve the quadratic equation

            Rb = [90.09 ±\sqrt{90.09^2 - 4 \ 1801.8} ] / 2

            Rb = [90.09 ± 30.15] / 2

            Rb₁ = 60.12 ohm

            Rb₂ = 29.97 ohm

the smallest value is Rb = 30 ohm

When checking the answers, the correct one is D

6 0
3 years ago
HEEEEELLLPPPPPP!!!!!!!!!!! PPPPPPPPPPPLLLEAASSEE!!!
o-na [289]

Answer:

The arrows always start at the magnet's north pole and point towards its south pole. When two like-poles point together, the arrows from the two magnets point in OPPOSITE directions and the field lines cannot join up. So the magnets will push apart (repel).

4 0
3 years ago
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