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2 years ago

The hypothetical situation is described by a physics teacher: two equal mass objects moving at the same speed

Physics

1 answer:

arsen [322]2 years ago

8 0

Answer:

According to Newton's second law of motion, an object with a heavier mass will have more acceleration than an object with a smaller mass if both objects are moving with the same speed.

Explanation:

F=ma

a=F/m

a∝1/m

mass of any object is inversely proportional to its acceleration.

hence proved, an object with a heavier mass will have more acceleration than an object with a smaller mass if both objects are moving with the same speed.

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The tuning fork has a frequency of 426.7 is found to cause resonance in a closed column of air measuring 0.186 (the diameter of

lidiya [134]

Answer:

The velocity of the tuning fork sound is 317.4648 m/s

Explanation:

The given parameters are;

The frequency of the fork, f = 426.7 Hz

The length of the closed air column, L = 0.186 m

The diameter of the tube, d = 0.15 m

At the fundamental frequency in a closed tube, we have;

λ = 4·L

Where;

λ = The wavelength of the wave

L = The length of the tube

From the equation for the velocity of a wave, we have;

v = f·λ

Where;

v = The velocity of the (sound) wave

f = The frequency of the wave = 426.7 Hz

λ = 4·L = 4 × 0.186 m = 0.744 m

∴ v = 426.7 Hz × 0.744 m = 317.4648 m/s

Therefore, the velocity of the sound produced by the tuning fork, v = 317.4648 m/s

3 0

3 years ago

Describe what a high and low frequency electromagnetic wave look like:

Ghella [55]

A high electromagnetic wave has short, very fast, frequent waves.

a low electromagnetic wave has long, very slow, infrequent waves.

hope this helps! pls mark brainliest!

4 0

2 years ago

Einstein and Lorentz, being avid tennis players, play a fast-paced game on a court where they stand 25.0 m from each other. Bein

Lerok [7]

Answer:

A) 199.78 J

B) 9.292x10^14 J

C) 4.2x10^7 m/s

D) 0.65 m

E) 1.13x10^-8 sec

D) 2.94x10^-9 sec

Explanation:

mass of ball = 0.0580 kg

If smashed at v = 83.0 m/s, KE is

KE = 0.5mv^2

= 0.5 x 0.0580 x 83.0^2

= 199.78 J

B) if returned at v = 1.79×10^8 m/s, KE will be

KE = 0.5mv^2

= 0.5 x 0.0580 x (1.79×10^8)^2

= 9.292x10^14 J

C) during Einstein's return, velocity of rabbit relative to players is

Vr = 2.21×108 m/s

Rabbit's velocity relative to ball = 2.21×10^8 - 1.79×10^8

= 4.2x10^7 m/s

D) the rabbit's speed approaches the speed of light so we consider relativistic effect. The rabbit's measured distance is

l = l°( 1 - v^2/c^2)

= 2.5(1 - 2.21/3)

= 2.5 x 0.26

= 0.65 m

E) according to the players, the time taken by the rabbit is

t = d/v = 2.5/ 2.21×10^8

= 1.13x10^-8 sec

F) the time for rabbit as measured by rabbit is relativistic

t = t°( 1 - v^2/c^2)

= 1.13x10^-8 (1 - 2.21/3)

= 1.13x10^-8 x 0.26

= 2.94x10^-9 sec

7 0

3 years ago

A pendulum can be formed by tying a small object, like a tennis ball, to a string, and then connecting the other end of the stri

Usimov [2.4K]

Answer:

1- t^3

2- t^2

3- t1

Explanation:

The acceleration produced in a body, while travelling in a circular motion, due to change in direction of motion is called centripetal acceleration. The formula of the centripetal acceleration is as follows:

ac = v²/r

where,

ac = centripetal acceleration

v = speed

r = radius

for a constant radius the centripetal acceleration will be directly proportional to the speed of object. The speed of pendulum will be lowest at t1 due to zero speed initially. Then the speed will increase gradually having greater speed at t^2 and the highest speed and centripetal acceleration at t^3. Therefore, the three instants in tie can be written in following order from greatest centripetal acceleration to lowest:

5 0

2 years ago

1.2 m long spring with a spring force of 200.0 N/m, 12.0 kg mass is attached to it, find the length

Crank

From Hooke's law, the length of the spring after extension and after the mass is attached is 1.788 meters. Option B is the answer.

<h3>HOOKE'S LAW</h3>

Hooke's law state that in an elastic material, the force applied is directly proportional to the extension provided that the elastic limit is not exceeded.

Given that a 12.0 kg mass is attached to 1.2 m long spring with a spring constant of 200.0 N/m.

The given parameters are:

mass m = 12kg

Initial length $L_{1}$ = 1.2 m

Spring constant K = 200 N/m

Extension e = ?

According to Hooke's law

F = Ke

But F = mg

mg = Ke

Substitute all the parameters into the formula to get extension e

12 x 9.8 = 200e

e = 117.6 / 200

e = 0.588 m

The length of the spring after extension and after the mass is attached will be

$L_{2}$ = $L_{1}$ + e

$L_{2}$ = 1.2 + 0.588

$L_{2}$ = 1.788 m

Therefore, the correct answer is option B because the length of the spring after extension and after the mass is attached is 1.788 meters.

Learn more about Hooke's law here: brainly.com/question/12253978

3 0

1 year ago

Read 2 more answers