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olga nikolaevna [1]

3 years ago

9

The hypothetical situation is described by a physics teacher: two equal mass objects moving at the same speed

1 answer:

arsen [322]3 years ago

8 0

Answer:

According to Newton's second law of motion, an object with a heavier mass will have more acceleration than an object with a smaller mass if both objects are moving with the same speed.

Explanation:

F=ma

a=F/m

a∝1/m

mass of any object is inversely proportional to its acceleration.

hence proved, an object with a heavier mass will have more acceleration than an object with a smaller mass if both objects are moving with the same speed.

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If an astronaut throws an object in space, the object's speed will _____________. A) decrease. B) increase. C) remain constant.

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The object's speed will remain constant after the it leaves his hand.

So will HIS speed in the opposite direction.

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3 years ago

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Why do atoms do group 1 element lose electrons to form cations

Mrac [35]

Answer:

when a element of 1 group take part in reaction, its atom looses outer electron and form positively charged ions called Cation.

Explanation:

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3 years ago

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jeka94

Answer:

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2 years ago

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The force on the spring is F0 and it stores elastic potential energy PEs0. If the spring displacement is tripled to 3x0, determi

Dimas [21]

Answer:

Explanation:

Let initial extension in the spring= x₀

Force on the spring = F₀

Let spring constant = k

Fo = k x₀

Fn = 3k x₀

Fn /Fo = 3

PEs0 ( ORIGINAL) =1/2 k x₀²

PEsn ( NEW) =1/2 k (3x₀)²

PEsn / PEs0 = 9

7 0

3 years ago

A small branch is wedged under a 200 kg rock and rests on a smaller object. The smaller object is 2.0 m from the large rock and

Alexxandr [17]

Answer:

a

$F =326.7 \ N$

b

$M = 6$

Explanation:

From the question we are told that

The mass of the rock is $m_r = 200 \ kg$

The length of the small object from the rock is $d = 2 \ m$

The length of the small object from the branch $l = 12 \ m$

An image representing this lever set-up is shown on the first uploaded image

Here the small object acts as a fulcrum

The force exerted by the weight of the rock is mathematically evaluated as

$W = m_r * g$

substituting values

$W = 200 * 9.8$

$W = 1960 \ N$

So at equilibrium the sum of the moment about the fulcrum is mathematically represented as

$\sum M_f = F * cos \theta * l - W cos\theta * d = 0$

Here $\theta$ is very small so $cos\theta * l = l$

and $cos\theta * d = d$

Hence

$F * l - W * d = 0$

=> $F = \frac{W * d}{l}$

substituting values

$F = \frac{1960 * 2}{12}$

$F =326.7 \ N$

The mechanical advantage is mathematically evaluated as

$M = \frac{W}{F}$

substituting values

$M = \frac{1960}{326.7}$

$M = 6$

6 0

3 years ago