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Step2247 [10]
3 years ago
5

The following is an idealized equation representing the world population of Leatherback turtles, where t represents time in year

s since 1970.
f(t) = 50,000(.92)^t

How would you determine the population in the year 2000?

Is this a growth or a decay function?

How can you tell a growth or decay function just by looking at it?
Mathematics
1 answer:
IRINA_888 [86]3 years ago
7 0
In this case t = 2000 - 1970 = 30 
so population in 2000 = 50,000 * (0.92)^30  =  4098 Asawer
This is a function of decay.

The function is decay because the number in the parentheses is < 1. 
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Vlad1618 [11]

Answer:

24.6 < μ < 27.2

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{3.8}{\sqrt{34}} = 1.3

The lower end of the interval is the sample mean subtracted by M. So it is 25.9 - 1.3 = 24.6 pounds.

The upper end of the interval is the sample mean added to M. So it is 25.9 + 1.3 = 27.2 pounds.

So the correct answer is:

24.6 < μ < 27.2

4 0
3 years ago
Solve for d. 1.2+d+0.4=9.7
Advocard [28]
Move everything around. d+1.6=9.7. d=8.1.
3 0
3 years ago
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Leila wrote an equation to represent the revenue of a parking lot for one day. She let x represent the number of cars that paid
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Reptile [31]

Answer:

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