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Rasek [7]
3 years ago
11

Thanks a lot you helped me fail my test

Chemistry
1 answer:
lions [1.4K]3 years ago
8 0

Answer:

they help me fail my test too

Explanation:

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How many moles of \ce{Fe2O3}FeX 2 ​ OX 3 ​ will be produced from 27.0 \text{ g}27.0 g27, point, 0, start text, space, g, end tex
ira [324]

Answer : The number of moles of Fe_2O_3  produced will be, 0.241 moles.

Solution : Given,

Mass of Fe = 27.0 g

Molar mass of Fe = 56 g/mole

First we have to calculate the moles of Fe.

\text{ Moles of }Fe=\frac{\text{ Mass of }Fe}{\text{ Molar mass of }Fe}=\frac{27.0g}{56g/mole}=0.482moles

Now we have to calculate the moles of Fe_2O_3

The balanced chemical reaction is,

4Fe+3O_2\rightarrow 2Fe_2O_3

From the reaction, we conclude that

As, 4 mole of Fe react to give 2 mole of Fe_2O_3

So, 0.482 moles of Fe react to give \frac{0.482}{4}\times 2=0.241 moles of Fe_2O_3

Thus, the number of moles of Fe_2O_3  produced will be, 0.241 moles.

6 0
3 years ago
Jonathan is working in his basement on a science fair project when his little sister closes and locks the door. Jonathan wants t
solmaris [256]

Answer:

he can bang metal pipes but i would rather say that he has to yell for help

Explanation:

why because the basement is very loud and echo so when is parents hear him they can run to basement and get him out

hope this helped

4 0
3 years ago
Read 2 more answers
How many grams of glucose are needed to prepare 144.3 mL of a 1.4%(m/v) glucose solution?
Montano1993 [528]

Answer:

2.0202 grams

Explanation:

1.4% (m/v) glucose solution means: 1.4g glucose/100mL solution.

so ?g glucose = 144.3 mL soln

Now apply the conversion factor, and you have:

?g glucose = 144.3mL soln x (1.4g glucose/100mL soln).

so you have (144.3x1.4/100) g glucose= 2.0202 grams

6 0
3 years ago
Read 2 more answers
Please help asap thank you.
Aleks [24]

Answer:

a)0.816g/l

b)0.241g/l

8 0
3 years ago
A student is asked to identify and element that is pale yellow brittle solid and does not conduct electricity. At which location
disa [49]

Answer:

Far right

Explanation:

The qualities indicated here are of the element Sulphur (S) and any element of same qualities i.e color pale yellow, nature solid, electrical conductivity none, should be placed at far right corner of the periodic table or position 3 mentioned in the attached picture.

Hope it help!

3 0
3 years ago
Read 2 more answers
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