<h3><u>Answer;</u></h3>
= 12.5 Moles of CaSO3
<h3><u>Explanation</u>;</h3>
The reaction between CaCO3 and SO2 is given by the equation.
CaCO3(s) + SO2(g) → CaSO3(aq) + CO2(g)
The mole ratio between CaCO3 and SO2 is 1 : 1;
1 mole of CaCO3 reacts with 1 mole SO2 to form CaSO3 and CO2
Therefore;
<em>12.5 moles of SO2 will require 12.5 moles of CaSO3</em>
Answer:
0.00370 g
Explanation:
From the given information:
To determine the amount of acid remaining using the formula:
where;
v_1 = volume of organic solvent = 20-mL
n = numbers of extractions = 4
v_2 = actual volume of water = 100-mL
k_d = distribution coefficient = 10
∴
Thus, the final amount of acid left in the water = 0.012345 * 0.30
= 0.00370 g
Answer:
the normality of the given solution is 0.0755 N
Explanation:
The computation of the normality of the given solution is shown below:
Here we have to realize the two sodiums ions per carbonate ion i.e.
N = 0.321g Na_2CO_3 × (1mol ÷ 105.99g)×(2eq ÷ 1mol)
= 0.1886eq ÷ 0.2500L
= 0.0755 N
Hence, the normality of the given solution is 0.0755 N
Answer:
A double bond between carbon atoms
Explanation:
The suffix -ene is used for alkenes, which tells you that the molecule has a carbon-carbon double bond.
