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Mkey [24]
3 years ago
15

3. How do you observe stuff?

Chemistry
2 answers:
mote1985 [20]3 years ago
8 0

Answer:

by looking at the and researching for super long

Explanation:

amid [387]3 years ago
8 0
By reaching or looking
You might be interested in
Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and
coldgirl [10]

Answer :

a. The oxidizing agent is: BH_4^-

b. The reducing agent is: ClO_3^-

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

BH_4^-(aq)+ClO_3^-(aq)\rightarrow H_2BO_3^-(aq)+Cl^-(aq)

The oxidation-reduction half reaction will be :

Oxidation : BH_4^-\rightarrow H_2BO_3^-

Reduction : ClO_3^-\rightarrow Cl^-

Now balance oxygen atom on both side.

Oxidation : BH_4^-\rightarrow H_2BO_3^-+3H_2O

Reduction : ClO_3^-+3H_2O\rightarrow Cl^-  

Now balance hydrogen atom on both side.

Oxidation : BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O

Reduction : ClO_3^-+3H_2O\rightarrow Cl^-+6OH^-

Now balance the charge.

Oxidation : BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O+4e^-

Reduction : ClO_3^-+3H_2O+6e^-\rightarrow Cl^-+6OH^-

In order to balance the electrons, we multiply the oxidation reaction by 6 and reduction reaction by 4 and then added both equation, we get the balanced redox reaction.

Oxidation : 6BH_4^-+24OH^-\rightarrow 6H_2BO_3^-+18H_2O+24e^-

Reduction : 4ClO_3^-+12H_2O+24e^-\rightarrow 4Cl^-+24OH^-

The balanced chemical equation in acidic medium will be,

6BH_4^-+4ClO_3^-\rightarrow 6H_2BO_3^-+6H_2O+4Cl^-

3BH_4^-+2ClO_3^-\rightarrow 3H_2BO_3^-+3H_2O+2Cl^-

In the redox reaction, ClO_3^- act as oxidizing agent and BH_4^- act as an reducing agent.

7 0
3 years ago
How many moles are in 156 grams of potassium???<br><br><br> I already tried to ask google : (
Y_Kistochka [10]

Answer:

1 mole is equal to 1 moles Potassium, or 39.0983 grams.

39.0983g X 4 = 156.3932

so 4 moles are in 156 grams of Potassium

Explanation:

Hope this helps

-A Helping Friend (mark brainliest pls)

5 0
4 years ago
Read 2 more answers
Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the following reaction equation. 2H202(aq)
inn [45]

Answer : The temperature for non-catalyzed reaction needed will be 456 K

Explanation :

Activation energy : The energy required to initiate the reaction is known as activation energy.

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

Since, the rate for both the reaction are equal.

K_1=K_2

A\times e^{\frac{-Ea_1}{RT_1}}=A\times e^{\frac{-Ea_2}{RT_2}}

\frac{Ea_1}{T_1}=\frac{Ea_2}{T_2} ..........(1)

where,

Ea_1 = activation energy for non-catalyzed reaction = 75 kJ/mol

Ea_2 = activation energy for catalyzed reaction = 49 kJ/mol

T_1 =  temperature for non-catalyzed reaction = ?

T_2 = temperature for catalyzed reaction = 25^oC=273+25=298K

Now put all the given values in the above formula 1, we get:

\frac{Ea_1}{T_1}=\frac{Ea_2}{T_2}

\frac{75kJ/mol}{T_1}=\frac{49kJ/mol}{298K}

T_1=456K

Therefore, the temperature for non-catalyzed reaction needed will be 456 K

3 0
3 years ago
How many mL of a 1.50 M solution of cobalt(III) sulfate are required to make 400.0 mL of a 0.850 M solution of cobalt(III) sulfa
serious [3.7K]

Answer:

Answer. 600 g CaCl2 would be required to make 2 L of a 3.5 M solution.

7 0
4 years ago
A material absorbs or reflects all of the light that reaches it. What type of material is it?
Tanya [424]
Material that absorbs or reflects all light that reaches it is called opaque. 

An object is translucent when it allows some light to go through and reflects the others It is transparent when all light goes through it. Pigmented on the other hand changes the color of the light. 

The answer is D.
7 0
3 years ago
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