Answer:
Amount of salt needed is around 2.3*10³ g
Explanation:
The salt content in sea water = 3.5 %
This implies that there is 3.5 g salt in 100 g sea water
Density of seawater = 1.03 g/ml
Volume of seawater = volume of tank = 62.5 L = 62500 ml
Therefore, the amount of seawater required is:
![=Density*Volume = 1.03g/ml*62500ml = 6.44*10^{4} g](https://tex.z-dn.net/?f=%3DDensity%2AVolume%20%3D%201.03g%2Fml%2A62500ml%20%3D%206.44%2A10%5E%7B4%7D%20g)
The amount of salt needed for the calculated amount of seawater is:
![=\frac{6.44*10^{4}g\ water*3.5g\ salt }{100g\ water} =2254 g =2.3*10^{3} g](https://tex.z-dn.net/?f=%3D%5Cfrac%7B6.44%2A10%5E%7B4%7Dg%5C%20water%2A3.5g%5C%20salt%20%7D%7B100g%5C%20water%7D%20%3D2254%20g%20%3D2.3%2A10%5E%7B3%7D%20g)
A. The substance dissolved. Just because a substance dissolved in a solvent doesn’t mean that a chemical action occurred. For example, if you put sugar in water as stir, it will dissolve, but the chemical make up of the sugar and the water don’t change. A chemical reaction can be indicated by a drastic change in color or temperature or if a substance precipitate.
Hope this helped :)
The rate of dissolution of a solid solute into the solution decreases when you stop stirring it. Generally, stirring increases the dissolution rate of a solid into a solution. An example is coffee with sugar, the sugar dissolves faster when stirred versus when left to dissolve on its own.
Generally, chemists prefer to use morality (B) because it only invovles measuring the final volume of the solution and amount of moles of the solute
Hope this helps
Answer:
The boiling point increases with increased pressure up to the critical point, where the gas and liquid properties become identical.