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guapka [62]
3 years ago
9

Someone please answer i’ll give you brainly.

Chemistry
1 answer:
lina2011 [118]3 years ago
4 0
Let's hope she didn't watch it without me or i will never be speaking to her again :))
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An air-filled balloon has a volume of 225 L at 0.940 atm and 25 °C. Soon after, the pressure changes to 0.990 atm and the temper
lorasvet [3.4K]

Answer:

The right choice is  V₂ = 195.7 L

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V: is the volume of the gas in L.

n: is the no. of moles of the gas in mol.

R:  is the general gas constant,

T: is the temperature of the gas in K.

If n is constant, and have different values of P, V and T:

(P₁*V₁) / T₁ = (P₂ * V₂) / T₂

Knowing that:  

V₁  =  225 L  ,         P₁ = 0.940 atm

T₁ = 25  °C + 273  =  298 K

V₂  =  ??? L,           P₂ = 0.990 atm  

T₂ = 0 °C + 273  =  273 K

applying in the above equation

(P ₁* V₁) / T₁ = (P₂ * V₂) / T₂

(0.940 atm * 225 L) / 298 K= (0.990 atm  * V₂) / 273 K

V₂ = (0.940 atm * 225 L * 273 K) / (298 K * 0.990 atm)

V₂ = 195.7 L

So, the right choice is:

V₂ = 195.7 L

7 0
3 years ago
Why is coal known as buried sunshine
Monica [59]
Can u send a picture so I know wat ur talking about
8 0
3 years ago
Please help!!!!!!!!!!!
Viefleur [7K]

Answer:

b

Explanation:

and if that wrong let me know cause jm my science class its b

7 0
3 years ago
Which of the following reactions would have an increase in entropy?
lana66690 [7]

Answer:

D. CH₄(g) + H₂O(g) → CO(g) + 3H₂(g)

Explanation:

A rule of thumb is that there's an increase in entropy if there are more molecules in the products than in the reactants when there's no state change. The only given option where that takes place is option D., as there are two molecules in the reactants and 4 (1 of CO and 3 of H₂) in the products.

7 0
3 years ago
Read 2 more answers
2.0 cm + 2.6 cm + 4.2 mm =<br><br> Please show work
Setler [38]
Hi ;)!
So:
4.2 mm (/10) = 0.42 cm

2.0 cm + 2.6 cm + 0.42 cm =  5.02 cm ;)
3 0
3 years ago
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