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3 years ago

5

Kevin is 3 years older than daniel. Two years ago, Kevin was 4 times as old as Daniel. Let k be Kevin's age and let d be Daniels

age. What system of equations would represent this situation?

1 answer:

IRISSAK [1]3 years ago

6 0

Answer:not 100% sure but i think it is d+3-2x4

Step-by-step explanation:

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Solve the following questions <br> 1/6x + 2/3=1/4x-1/3

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2 years ago

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natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

<u>Recall:</u>

Binomial Distribution --> $P(k)={n\choose k}p^kq^{n-k}$
$P(k)$ denotes the probability of $k$ successes in $n$ independent trials
$p^k$ denotes the probability of success on each of $k$ trials
$q^{n-k}$ denotes the probability of failure on the remaining $n-k$ trials
${n\choose k}=\frac{n!}{(n-k)!k!}$ denotes all possible ways to choose $k$ things out of $n$ things

<u>Given:</u>

$n=10$
$k=4$
$p^k=0.53^4$
$q^{n-k}=(1-0.53)^{10-4}=0.47^6$
${n\choose k}={10\choose 4}=\frac{10!}{(10-4)!4!}=210$

<u>Calculate:</u>

$P(4)=(210)(0.53^4)(0.47^6)=0.1786117069\approx0.179$

Therefore, the probability that the archer will get exactly 4 bull's-eyes with 10 arrows in any order is 0.179

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1 year ago

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Answer:

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