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3 years ago

Can someone answer questions 1-3 please.

Physics

1 answer:

Lunna [17]3 years ago

4 0

Answer:

Question 1 is C.

thats all ik

Explanation:

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How many seconds of space should you keep between you if you're driving a 100 foot truck 30 mph?

Marrrta [24]

Answer:

 The space in seconds that will be kept = 2.27 seconds

Explanation:

S = d/t..................... Equation 1

making t the subject of formula in the equation above,

t = d/S.................... Equation 2

Where S = speed, d = distance, t = time.

Conversion: (i)if 1 mph = 0.44704 m/s,

then, 30 mph = 30×0.44704

= 13.41 m/s

(ii) If 1 foot = 0.3048 m

then, 100 foot = 30.48 m.

Given: S = 30 mph = 13.41 m/s, d = 100 foot = 30.48 m

Substituting these values into equation 2

t = 30.48/13.41

t = 2.27 seconds.

Therefore the space in seconds that will be kept = 2.27 seconds

7 0

3 years ago

The sound from a single source can reach point O by two different paths. One path is 20.0 m long and the second path is 21.0 m l

aleksandrvk [35]

Answer:

minimum frequency = 170 Hz

Explanation:

given data

One path long = 20 m

second path long = 21 m

speed of sound = 340 m/s

solution

we get here destructive phase that is path difference of minimum $\frac{\lambda}{2}$

here λ is the wavelength of the wave

so path difference will be

21 - 20 = $\frac{\lambda}{2}$

λ = 2 m

and

velocity that is express as

velocity = frequency × wavelength .............1

frequency = $\frac{340}{2}$

minimum frequency = 170 Hz

7 0

3 years ago

An object is projected from the ground with an upward speed of ų m/s has a speed of 23m/s when it is at a height of 5m above the

vovikov84 [41]

Answer:

25.08m/s

Explanation:

mgh1 + 0.5mv1² = mgh2 + 0.5mv2²

h1 = 0m

v1 = u

h2 = 5m

v2 = 23m/s

putting the values into the formula above;

m(10)(0) + 0.5m(u²) = m(10)(5) + 0.5m(23²)

0 + 0.5mu² = 50m + 264.5m

0.5mu² = 314.5m

dividing through by m

0.5u² = 314.5

u² = 629

u = 25.08m/s

Therefore, the initial speed "u" = 25m/s

6 0

2 years ago

Arocket with an initial velocity of 20 m/s another engine that gives it an acceleration of 4 m/s ^ 2 over 10 secondsHow far did

ExtremeBDS [4]

Answer:

50m

Explanation:

Given parameters:

Initial velocity = 20m/s

Acceleration = 4m/s²

Time = 10s

Unknown:

Distance traveled by the rocket = ?

Solution:

To solve this problem use the expression below;

v² = u² + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

final velocity = 0

Insert the parameters and solve;

0² = 20² + 2 x 4 x s

-400 = 8s

s = 50m

Disregard the negative sign because distance cannot be negative.

3 0

2 years ago

As a mercury atom absorbs a photon of

Allisa [31]

The energy absorbed by photon is 1.24 eV.
This is the perfect answer.

8 0

2 years ago