Answer:
Options (3) and (6)
Explanation:
Janine drives 2.2 km East.
Since, distances measured in the East are positive,
Displacement = 2.2 km
Then she drives 4.4 km west
Displacement = -4.4 km
Followed by 1.7 km in the East
Displacement = 1.7 km
Total displacement = 2.2 - 4.4 + 1.7 = -0.5 km
km
Total distance covered by Janine = 2.2 + 4.4 + 1.7 = 8.3 km
d = 8.3 km
Therefore, Options (3) and (6) will be the answer.
First we need to turn Aouita's time for the race into seconds. There are
60 seconds in a minute, so 7 minutes and 29.45 seconds is (7 x 60) +
29.45 = 449.45. He ran 3000 meters in that time, so his average speed
was 3000 meters divided by 449.45 seconds. 3000 / 449.45 = 6.67 m/s. So,
on average, he covered 6.67 meters (more than 21 feet!) during each
second of the race.
Answer:
54 kg
Explanation:
Mass of person = 93 kg = 
Mass of water = 62 kg = 
Dividing the above two masses we get

Hence, the mass of the person is 1.5 times the mass of the water in them
Now, Mass of person = 81 kg = 

So, the mass of water in a person that has mass of 81 kg is 54 kg
Answer:
The minimum speed is 7.5 m/s.
Explanation:
Given that,
Height = 2.87 m
We need to calculate the minimum speed
Using equation of motion


Where, u = minimum velocity
g = acceleration due to gravity
h = height
Put the value into the formula


Hence, The minimum speed is 7.5 m/s.