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4 years ago

What is a non example of temperature

2 answers:

7 0

We measure temperature of matters with a device called thermometer. There are three types of thermometer, Celsius Thermometer, Fahrenheit Thermometer and Kelvin Thermometer.

Nimfa-mama [501]4 years ago

5 0

Best Answer

1) what do you mean "non -examples"

2) energy is something in the physical world. we cannot see fell hear touch etc

but it had different forms: work = pushing or pulling a distance, lifting, moving, heat, light sound electricity, . it is best understood by giving examples of the different forms.

it is an idea that is only about 400 years old in physics

It does NOT mean excitement, as "the football crowd had a lot of energy after the big game"

I like to say it is what ever it is, that allows physical change to happen

3) temperature is what we feel as hot or cold and is a measure of average heat energy of a material.

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The Indianapolis Motor Speedway has four banked curves, each of which forms a quarter of a circle. Suppose a race car speeds alo

boyakko [2]

Answer:

r = 255.68 m

Explanation:

When a body moves in a circular path, an acceleration, due to constant change in its direction, is developed, known as centripetal acceleration. The centripetal acceleration acts towards the center of the circular path. The formula to calculate the centripetal acceleration is given as follows:

ac = v²/r

where,

ac = centripetal acceleration = 22 m/s²

v = tangential speed = 75 m/s

r = radius of curve = ?

Therefore,

22 m/s² = (75 m/s)²/r

r = (75 m/s)²/(22 m/s²)

r = 255.68 m

4 0

3 years ago

A book falls off a shelf that and hits the ground at 10.0 m/s. How far did it fall?

ELEN [110]

Answer:

Explanation:

14 m/s

Explanation:

The motion of the book is a free fall motion, so it is an uniformly accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. Therefore we can find the final velocity by using the equation:

where

u = 0 is the initial speed

g = 9.8 m/s^2 is the acceleration

d = 10.0 m is the distance covered by the book

Substituting data, we find

8 0

3 years ago

Which of the following is NOT an illuminated object?

Korolek [52]

Answer:

The answer here would be light bulb.

Explanation:

An Illuminated object is simply something that reflects light. And everything in the list is illuminated except the light bulb. Humans reflect light in the same way as desks and sidewalks. If we didn't we wouldn't technically be able to see other humans unless they were luminous. This brings me to the nest point. A light bulb is a luminous object because it creates light on its own.

A good example would be this:

The Sun is a luminous object

The Moon is a illuminated object

I hope this helped and didn't confuse you more, I kind of went all over the place with the explanation. Either way, if you need more help feel free to let me know! :)

-Matt

5 0

3 years ago

Roads often have to be repaved because they crack over time. Sometimes this cracking is due to the fact that the roads (as well

Finger [1]

B. Physical Change - The molecules do not change shape or size. They do not contract or expand only.

4 0

3 years ago

Suppose a gliding 2-kg cart bumps into, and sticks to, a stationary 5-kg cart. If the speed of the gliding cart before the colli

Thepotemich [5.8K]

Answer:

Therefore,

Final velocity of the coupled carts after the collision is

$v_{f}=4\ m/s$

Explanation:

Given:

Mass of Glidding Cart = m₁ = 2 kg

Mass of Stationary Cart = m₂ = 5 kg

Initial velocity of Glidding Cart = u₁ = 14 m/s

Initial velocity of Stationary Cart = u₂ = 0 m/s

To Find:

Final velocity of the coupled carts after the collision = $v_{f}=?$

Solution:

Law of Conservation of Momentum:

For a collision occurring between two objects in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

It is denoted by "p" and given by

Momentum = p = mass × velocity

Hence by law of Conservation of Momentum we hame

Momentum before collision = Momentum after collision

Here after collision both are stuck together so both will have same final velocity,

$m_{1}\times u_{1}+m_{2}\times u_{2}=(m_{1}+m_{2})\times v_{f}$

Substituting the values we get

$2\times 14 + 5\times 0 =(2+5)\times v_{f}$

$v_{f}=\dfrac{28}{7}=4\ m/s$

Therefore,

Final velocity of the coupled carts after the collision is

$v_{f}=4\ m/s$

8 0

3 years ago