Answer:
A. 6.282
B. 2.03kg
Explanation:
A.
We solve using archimedes principle
L³pwood = L²dwater
We make d subject of the formula
d = Lpwood/pester
= 18x651/1000
= 18x0.651
= 11.718cm
Distance from horizontal top to water level
= 18-11.718
= 6.282cm
B.
When we place lead block
WL + L³pwoodg = L³pwaterg
WL = L³g(Pwater-Pwood)
= 0.18³x9.8(1000-651)
= 19.94N
19.94/9.8
= 2.03kg
The mass m is therefore 2.03kg
Answer:
displacement is 41√2 m and 45º; velocity is 15 √2 m/s and 315º and the acceleration is 0.786 m/s² and 315º
Explanation:
a and b) The cyclist is at a distance east and then north, we can find the displacement using the Pythagorean theorem
Xt² = X1² + X2²
Xt = √(41² + 41²)
Xt = 41 √2 m
The angle can be found by trigonometry
tan θ = X1 / X2
tan θ = 41/41 = 1
θ = 45º
c and d) the velocities are also vector magnitudes, so they can be brought in the same way as the displacements
V² = V1² + V2²
V = √ V1² + V2²
V = √[(-15)² + 15²
V = 15 √2 m/s
Tan θ = -15/15 = -1
θ = -45º
This is (270+ 45) measured from the east counterclockwise
θ = 315º
E and f) the average accelerations
Let's calculate the value of acceleration, which is also a vector
a = (Vf -Vo )/ t
The initial speed is directed south is negative and the final speed is directed east is positive
Vf = 15 m/s i^ θ = 0º
Vo = -15 m/s j^ θ = 270º
a = (15 i^ - (- 15) j^) / 27
cañculate the module
a² = (Vf² + Vo²) / t²
a = √ (15² + 15²) / 27
a = 15 √2 /27
a = 0.786 m/s²
The direction of acceleration is
tan θ = ay / ax
tan θ = -0.55 / 0.55 = -1
θ = -45º
This is (270+ 45) measured from the east counterclockwise
The speed of a proton after it accelerates from rest through a potential difference of 350 V is .
Initial velocity of the proton
Given potential difference
let's assume that the speed of the proton is ,
Since the proton is accelerating through a potential difference, proton's potential energy will change with time. The potential energy of a particle of charge when accelerated with a potential difference is,
Due to Work-Energy Theorem and Conservation of Energy - <em>If there is no non-conservative force acting on a particle then loss in Potential energy P.E must be equal to gain in Kinetic Energy K.E</em> i.e
If the initial and final velocity of the proton is and respectively then,
change in Kinetic Energy
change in Potential Energy
from conservation of energy,
so,
To read more about the conservation of energy, please go to brainly.com/question/14668053
Out of the following given choices;
a. decelerate; accelerate
b. accelerate; decelerate
c. stop; accelerate
d. decelerate; stop
<span>The answer is B. This is because
the cold front usually rotates around the warm front as cold air mass coverage
in the low-pressure system. This causes the cold air mass to accelerate to
catch up with the warm front. When an occluded front ( that is the boundary
that separates the older cool air mass already in place from new incoming cold
air mass), that the system decelerates. </span>
Answer:
k=0.0577w/mk
k=0.03338BTU/h-ft-ºF
Explanation:
First we use the equation for heat transfer by conduction and solve for K
Q=KA(T2-T1)/x
Where
q=heat
A=area
T=temperature
K=conductivity
x=thickness
solving for k
k=Qx/A(T2-T1)
Q/A=Heat flux=q
k=qx/(T2-T1)
k=35.1*0.025/(318.4-303.2)
K=0.0577w/mk
remember that 1 btu / hftk equals 1,729 w / mk
K=0.0577/1.729=0.03338BTU/h-ft-ºF