Answer:
zero ( 0) times.
Explanation:
In the code;
i = 2
while ( i > 2){
i = floor( i/2 );
z = z + 1;
}
the variable " i " is assigned the integer " 2 ", then the while statement loops with a condition of a greater " i " value and divides the value by two for every loop.
But in this case, the while statement is not executed as the value of " i " which is 2 is not greater than but equal to two.
Answer:
C++.
Explanation:
#include <iostream>
#include <string>
using namespace std;
////////////////////////////////////////////////////////////
class Television {
string brand;
float screen_size;
bool powerOn;
int volume;
int channel;
public:
// Comments
Television(string brand, int screen_size) {
this->brand = brand;
this->screen_size = screen_size;
powerOn = false;
volume = 20;
channel = 2;
}
//////////////////////////////////////////
// Comments
int getVolume() {
return volume;
}
// Comments
int getChannel() {
return channel;
}
// Comments
string getManufacturer() {
return brand;
}
// Comments
float getScreenSize() {
screen_size;
}
///////////////////////////////////////////
// Comments
void setChannel(int channel) {
this->channel = channel;
}
// Comments
void power() {
if (!powerOn)
powerOn = !powerOn;
}
// Comments
void increaseVolume() {
volume = volume + 1;
}
// Comments
void decreseVolume() {
volume = volume - 1;
}
};
Answer is
5 minutes
The default value for windows 8.1 joined to a
server 2003 domain logon scripts delays is not configured. However, the windows
8.1 may have a delay processing logon scripts of 5 minutes. The script does not
execute until 5 minutes are over. Users have a Group policy applied to them
that is used to assign a logon script.
Answer:
False
Explanation:
Kleene star is a unary operation, we can perform this on a character or set of strings.It means zero or more than zero up to infinite.
It is represented by Vˣ or V+.
For 1, the kleene star will be empty string '∈' or any number of strings.
1ˣ =(∈,1,11,111,1111,11111......)
In question, the empty string '∈' is not present.
