The statements that correctly describe the time complexity of data structures with N data are:
- The average time complexity of the data lookup in a hash table is O(N).
- The average time complexity of inserting data into a heap is O(logN)
<h3>What is time complexity of data structures?</h3>
Time Complexity of an algorithm is known to be the depiction of the amount of time needed by the algorithm to carry out to completion.
Note that The statements that correctly describe the time complexity of data structures with N data are:
- The average time complexity of the data lookup in a hash table is O(N).
- The average time complexity of inserting data into a heap is O(logN)
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Answer:
negatives = []
zeros = []
positives = []
while True:
number = input("Enter a number: ")
if number == "":
break
else:
number = int(number)
if number < 0:
negatives.append(number)
elif number == 0:
zeros.append(number)
else:
positives.append(number)
for n in negatives:
print(n)
for z in zeros:
print(z)
for p in positives:
print(p)
Explanation:
Initialize three lists to hold the numbers
Create a while loop that iterates until the user enters a blank line
Inside the loop:
If the number is smaller than 0, put it in the negatives list
If the number is 0, put it in the zeros list
Otherwise, put the number in the negatives list
When the while loop is done, create three for loops to print the numbers inside the lists
Answer:
The flashdrive can hold 35389 400-pages-books
Explanation:
If
of a page occupies 1 kB of memory, we can calculate how much memory a book will take

Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.
To do the calculation, we have to know how many kilobytes are in 9 gigabytes.
There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:

Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.

The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.
Answer:
i think you can layer it :)
Explanation:
nice drawing btw!