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storchak [24]
3 years ago
13

The work of a student to solve the equation 2(3x − 4) = 8 + 2x + 4 is shown below:

Mathematics
2 answers:
mario62 [17]3 years ago
6 0
The correct answer is "<span>Step 2; 6x − 8 = 12 + 2x."
</span>
The step that the student first make an error is at the 2nd step. The correct step should be 6x − 8 = 12 + 2x.

Finishing the steps:
<span>Step 1: 2(3x − 4) = 8 + 2x + 4
</span>Step 2: <span>6x − 8 = 12 + 2x.
Step 3: 4x = 20
Step 4: x = 5</span>
Solnce55 [7]3 years ago
3 0

Answer:

Step 2; 6x − 8 = 12 + 2x

Step-by-step explanation:

Step 1: Write the equation

2(3x-4)=8+2x+4

Step 2: Apply distributive property to the left side and sum the constants to the right side

2(3x-4)=(8+4)+2x\\(2*3x)-(2*4)=12+2x\\6x-8=12+2x

Step 3: Subtract 2x from both sides and add 8 to both sides:

6x-8=12+2x\\6x-2x+8-8=12+8+2x-2x\\4x=20

Step 4: Divide both sides by 4:

x=\frac{20}{4} =5

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Answer:

1/5

Step-by-step explanation:

y  = kx  where k is the constant of proportionality

6  = k 30

Divide each side by 30

6/30 = k 30/30

1/5 = k

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The area of a rectangular city park is 25/54 square miles. The length of the park is 5/9 mile. What is the width, in miles, of t
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Area of rectangle = 24/54 square miles
length(L) = 5/9 miles
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3 years ago
Six years ago, Lucia’s age was 1/3 the age she will be in 6 years. How old is Lucia now? Enter an integer.
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Answer:

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7 0
1 year ago
Graph each equation<br> Y=-2|-3X+3|+4<br><br> NEED HELP ASAP!!
HACTEHA [7]

Graph the absolute value by using the vertex and a few selected points

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what is the standard form of the equation of a circle with the center 16,4 and a radius of 2 radical 2
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Answer:

(x - 16)² + (y - 4)² = 8

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (16, 4) and r = 2\sqrt{2}, thus

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