Answer:
Probability that the proportion in our sample of red candies will be less than 20% is 0.5 .
Step-by-step explanation:
We are given that 20% of the candy produced are red. A random sample of 100 bags of Skittles is taken.
The distribution we can use here is;
~ N(0,1)
where, p = 0.20 and n = 100
Let 
= proportion of red candies in our sample
So, P( < 0.20) = P( < 
) = P(Z < 0) = 0.5
Therefore, probability that the proportion in our sample of red candies will be less than 20% is 0.5 .
The problem statement appears to be trying to tell you that 60 million barrels of crude were processed, resulting in 34% of that volume being turned into gasoline, which was then sold for a total of $408 million. You are asked for the revenue associated with 1 barrel of gasoline.
($408·10^6)/(60·10^6 bbl × 0.34) = $408/(20.4 bbl) = $20/bbl
The income from one barrel of gasoline is $20.00.
<span>∑ from 1 to infinity of n^2* e^(-2n) = (e^2 + e^4)/(e^2 - 1)^3 = 0.23768</span>
Answer:
120,000
Step-by-step explanation:
8 times 10 to the 4th power is 80,000 and 4 times 10 to the 4th power is 40,000 and 80,000 plus 40,000 is 120,000
