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3 years ago

Y=x+2 4x+3y= -36 system of equation

Mathematics

2 answers:

ehidna [41]3 years ago

8 0

Answer:

A) Y=x+2

B) 4x+3y= -36

we rearrange A) as -x + Y =2 and multiply it by 4

A) -4x + 4y = 8 then we add B)

B) 4x +3y = -36

7y = -28

y = -4

A) -4 = x +2

x = -6

Step-by-step explanation:

Free_Kalibri [48]3 years ago

4 0

Answer:

(-6, -4)

Step-by-step explanation:

Use substitution.

Since y is already isolated, substitute it into the y of: 4x+3y=-36.

You should get: 4x+3(x+2)=-36

Simplify this and you'll get:

4x+3x+6=-36

Add both of the variables:

7x+6=-36

Add -6 to both sides, (because there is a -36 on one side, and a 6 on the other, you have to add a negative to eliminate the 6 whilst adding to the -36)

7x=-42

Divide both sides by 7:

x=-6

Now substitute this into y=x+2

y=-6+2

y=-4

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Step-by-step explanation:

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$\frac{-6+\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\=\frac{-6+\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{8}\\\\Let\: simplify\: ; -6+2\sqrt{29}\\=-2\times \:3+2\sqrt{29}\\=2\left(-3+\sqrt{29}\right)\\=\frac{2\left(-3+\sqrt{29}\right)}{8}\\=\frac{-3+\sqrt{29}}{4}\\$

$\frac{-6-\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\\\=\frac{-6-\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\\\=\frac{-6-\sqrt{116}}{2\times \:4}\\\\=\frac{-6-2\sqrt{29}}{8}\\\\=-\frac{2\left(3+\sqrt{29}\right)}{8}\\\\=-\frac{3+\sqrt{29}}{4}\\\\\\x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}$

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