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Vsevolod [243]
3 years ago
14

Y=x+2 4x+3y= -36 system of equation

Mathematics
2 answers:
ehidna [41]3 years ago
8 0

Answer:

A) Y=x+2

B) 4x+3y= -36

we rearrange A) as -x + Y =2 and multiply it by 4

A) -4x + 4y = 8 then we add B)

B) 4x +3y = -36

7y = -28

y = -4

A) -4 = x +2

x = -6


Step-by-step explanation:


Free_Kalibri [48]3 years ago
4 0

Answer:

(-6, -4)

Step-by-step explanation:

Use substitution.

Since y is already isolated, substitute it into the y of: 4x+3y=-36.

You should get: 4x+3(x+2)=-36

Simplify this and you'll get:

4x+3x+6=-36

Add both of the variables:

7x+6=-36

Add -6 to both sides, (because there is a -36 on one side, and a 6 on the other, you have to add a negative to eliminate the 6 whilst adding to the -36)

7x=-42

Divide both sides by 7:

x=-6


Now substitute this into y=x+2

y=-6+2

y=-4

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What is the remainder of (4x2 + 7x-1)= (4 + x)?<br>A. -9x – 1<br>B.23x – 1<br>C.35<br>D.-37​
bearhunter [10]

Answer: I don't know what you meant by remainder but i hope this helps :)

x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}\\

Step-by-step explanation:

\left(4x^2+7x-1\right)=\left(4+x\right)\\\mathrm{Refine}\\4x^2+7x-1=4+x\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\4x^2+7x-1-x=4+x-x\\Simplify\\4x^2+6x-1=4\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\4x^2+6x-1-4=4-4\\\mathrm{Simplify}\\4x^2+6x-5=0\\\mathrm{For\:}\quad a=4,\:b=6,\:c=-5:\\\quad x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}

\frac{-6+\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\=\frac{-6+\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{8}\\\\Let\: simplify\: ; -6+2\sqrt{29}\\=-2\times \:3+2\sqrt{29}\\=2\left(-3+\sqrt{29}\right)\\=\frac{2\left(-3+\sqrt{29}\right)}{8}\\=\frac{-3+\sqrt{29}}{4}\\

\frac{-6-\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\\\=\frac{-6-\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\\\=\frac{-6-\sqrt{116}}{2\times \:4}\\\\=\frac{-6-2\sqrt{29}}{8}\\\\=-\frac{2\left(3+\sqrt{29}\right)}{8}\\\\=-\frac{3+\sqrt{29}}{4}\\\\\\x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}

6 0
3 years ago
Read 2 more answers
I want to give brainliest one for every subject.
VikaD [51]

Can you please give me brainiest :D

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2 years ago
In ΔEFG , what is the approximate length of EF if the measure of angle G is 50° and FG is 10 cm?
swat32
Hey again, you can use trigonometric ratios for this one. You are trying to find the side length opposite of angle G, when you have the adjacent side length value known. You can use TOA, or tan((opposite/adjacent)) . Tan(50) = x/10 

X=  11.92 cm
6 0
3 years ago
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