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harkovskaia [24]
3 years ago
10

This is a tough one :/ If f(x) = -x + 7 and g(x) = radical of x– 3, what is (f º g)(4)

Mathematics
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

6

Step-by-step explanation:

To solve, first plug in 4 as your x value for your g(x) equation.

g(4)=\sqrt{4-3} \\g(4)=\sqrt{1} \\g(4)=1

Next, plug in the value of g(4) into your f(x) equation for x.

f(1)=-1+7\\f(1)=6

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Step-by-step explanation:

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Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck
Nimfa-mama [501]
\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}
\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}

Now, isolate the variables, so you can integrate.
(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}
\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}
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y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}

At x = 1, y = 0.
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0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C
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Circumference = 28.274 (3 d.p.)
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D would be true because if you think about it in percentage wise
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