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harkovskaia [24]
3 years ago
10

This is a tough one :/ If f(x) = -x + 7 and g(x) = radical of x– 3, what is (f º g)(4)

Mathematics
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

6

Step-by-step explanation:

To solve, first plug in 4 as your x value for your g(x) equation.

g(4)=\sqrt{4-3} \\g(4)=\sqrt{1} \\g(4)=1

Next, plug in the value of g(4) into your f(x) equation for x.

f(1)=-1+7\\f(1)=6

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1) Suppose there are 2 blue, 3 green, and 5 yellow marbles in a bag. One marble will be drawn from the bag. List the sample spac
Rama09 [41]

Answer:

2

Step-by-step explanation:

Simple

6 0
3 years ago
The density of a fluid is given by the empirical equation rho=70.5 exp(8.27 X 10^-7 P) where rho is density (lbm/ft^3) and P is
jasenka [17]

Answer:

(a) The unit of 70.5 is lbm/ft^3 and the unit of 8.27×10^-7 is in^2/lbf

(b) density = 0.1206g/cm^3

(c) rho = 0.1206exp(8.27×10^-7P)

Step-by-step explanation:

(a) The unit of 70.5 is the same as the unit of rho which is lbm/ft^3. The unit of 8.27×10^-7 is the inverse of the unit of P (lbf/in^2) because exp is found of a constant. Therefore, the unit of 8.27×10^-7 is in^2/lbf

(b) P = 9×10^6N/m^2

rho = 70.5exp(8.27×10^-7× 9×10^6) = 70.5exp7.443 = 70.5×1.71 = 120.6kg/m^3

rho = 120.6kg/m^3 × 1000g/1kg × 1m^3/10^6cm^3 = 0.1206g/cm^3

(c) Formula for rho (g/cm^3) as a function of P (N/m^2) is

rho = 0.1206exp(8.27×10^-7P) (the unit of 0.1206 is g/cm^3)

5 0
3 years ago
Q. Find the measure of QR
Andreas93 [3]

Answer: 22

Step-by-step explanation:

Since U is the midpoint of P and R, and S is the midpoint of P and Q, SU must be a midsegment.

By the midsegment theorem, SU is 1/2 the value of QR. Therefore QW = SU*2 = 11*2 = 22.

8 0
3 years ago
What is the x-intercept of y=40x+70
AysviL [449]
At th x-intercept y=o

∴40x + 70 = 0
  40x = -70
  x = -70/40
  x = -1.75

x intercepr = (-1.75,0)
8 0
3 years ago
Can someone please help!!!
RideAnS [48]

Answers:

  • System 1:  x = 3 and y = -5
  • System 2: x = 1 and y = 2

==========================================================

Explanation:

For now, let's focus on system 1.

We have identical copies of "2y" in each equation, which means that if we were to subtract the equations straight down, then the y terms cancel out. That allows us to solve for x.

  • The x terms subtract to 7x-x = 6x
  • The y terms subtract to 0 and go away
  • The right hand sides subtract to 11 minus (-7) = 11-(-7) = 11+7 = 18

After doing those subtractions, we have the new equation 6x = 18 which solves to x = 3. Divide both sides by 6 to isolate x.

Once we know x, we can find out y.

7x+2y = 11

7(3)+2y = 11

21+2y = 11

2y = 11-21

2y = -10

y = -10/2

y = -5

or we can say

x+2y = -7

3+2y = -7

2y = -7-3

2y = -10

y = -10/2

y = -5

We should lead to the same y value either way. This helps confirm we have the correct x value.

Overall, the solution to system 1 is (x,y) = (3, -5)

----------------------------

Now onto system 2.

Unfortunately, we don't have identical y terms this time. But what we can do is double everything in the second equation to go from -x+y = 1 to -2x+2y = 2.

The new equivalent system is

\begin{cases}7x+2y = 11\\-2x+2y = 2\end{cases}

Now we have the same situation as before: Subtract straight down, solve for x.

  • The x terms subtract to 7x-(-2x) = 7x+2x = 9x
  • The y terms go away when subtracting
  • The right hand sides subtract to 11-2 = 9

So we have 9x = 9 and that solves to x = 1.

We'll use this x to find the y value.

7x+2y = 11

7(1)+2y = 11

7+2y = 11

2y = 11-7

2y = 4

y = 4/2

y = 2

Or you could pick on the second equation

-x+y = 1

-1+y = 1

y = 1+1

y = 2

6 0
2 years ago
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