Ask question

Ask question

All categories

3 years ago

12

the strength s of a rectangular wooden beam is proportional to its width and the cube of is septh. If the beam is to be cut from

a log in the shape of a cylinder of radius 3 feet, express the strength S of the beam as a function of the width x. What is the domain of S

1 answer:

babymother [125]3 years ago

4 0

Answer:

Can see it in the pic

Explanation:

Can see it in the pic

You might be interested in

A suspension system is being designed for a 1300 kg vehicle. When the vehicle is empty, its static deflection is measured as 2.5

attashe74 [19]

Answer: damping coefficient = 1.5×10^5Ns/m

Explanation:

Please find the attached file for the solution

3 0

3 years ago

Start from 0 m/s and accelerate at 2m/s? Calculate the speed in m/s after acceleration for 5 seconds.

valentinak56 [21]

Answer:

10m/s

Explanation:

2m/s x 5s=10m/s

4 0

3 years ago

I need help with this physics

mestny [16]

Answer: I am so sorry, but i cannot answer this for you,i hope someone does though cause if i known Spanish i could have but i don't.

Explanation:

I hope you find someone that can help you answer this and i hope you have a Great Day! =)

6 0

3 years ago

What explains the key difference between a bomb calorimeter and a coffee cup calorimeter?.

Virty [35]

The key difference between a bomb calorimeter and a coffee cup calorimeter is high temperature.

<h3>What is bomb calorimeter?</h3>

A bomb calorimeter is an apparatus that can measure heats of combustion, used in various applications such as calculating the calorific value of foods and fuels.

<h3>What is coffee cup calorimeter?</h3>

A coffee cup calorimeter is a cup used to provide insulation when materials are mixed inside of it.

<h3>Difference between the two calorimeter</h3>

The coffee cup calorimeter can't be used for high-temperature reactions, either, because they would melt the cup.
A bomb calorimeter is used to measure heat flows for gases and high-temperature reactions

Learn more about calorimeter here: brainly.com/question/1407669

#SPJ1

3 0

2 years ago

A long, thin solenoid has 390 turns per meter and a radius of 1.20 cm. The current in the solenoid is increasing at a uniform ra

gtnhenbr [62]

To solve this problem it is necessary to apply the concepts related to Faraday's law and the induced emf.

By definition the induced electromotive force is defined as

$\int E dl = -\frac{d\phi}{dt}$

$\int E dl = -(\frac{dB}{dt})A$

Where,

$\phi =$ Electric field

B = Magnetic Field

A = Area

At the theory the magnetic field is defined as,

$B = \mu_0 NI$

Where,

N = Number of loops

I = current

$\mu_0 =$ Permeability constant

We know also that the cross sectional area, is the area from a circle, and the length is equal to the perimeter then

A = \pi r^2

l = 2\pi r

Replacing at the previous equation we have that

$E (2\pi r) = \mu_0 n (\frac{di}{dt})(\pi R^2)$

Where,

R = Radius of the solenoid

r = The distance from the axis

Re-arrange to find the current in function of time,

$\frac{di}{dt} = \frac{Er}{\mu_0 NR^2}$

Replacing our values we have

$\frac{di}{dt} = \frac{(8.00*10^{-6})(0.0348)}{(4\pi*10^{-7})(390)(1.2*10^-2)^2}$

$\frac{di}{dt} = 3.94487A/s$

8 0

3 years ago