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Elanso [62]
3 years ago
12

the strength s of a rectangular wooden beam is proportional to its width and the cube of is septh. If the beam is to be cut from

a log in the shape of a cylinder of radius 3 feet, express the strength S of the beam as a function of the width x. What is the domain of S

Physics
1 answer:
babymother [125]3 years ago
4 0

Answer:

Can see it in the pic

Explanation:

Can see it in the pic

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A 2kg Book is sitting on a table.a 10n Force is pulling to the right.a 3n Force is pulling to the left what is the net force act
salantis [7]


The net force = sum of all forces acting on the body



If we take left side as -ve and right side as +ve,
then,

The net force here would be equal to,
10N + (- 3N)
= 7N.


Therefore, a net force of +7N ( + indicates it's moving towards right) is acting on the book of mass 2kg.


4 0
3 years ago
What is the kinetic energy of a 3-kilogram bali that is rolling at 2 meters per second
alex41 [277]
6 jules


hope this helps
3 0
3 years ago
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A light-year is a measurement of _____.<br> a. time<br> b. gravity<br> c. energy<br> d. distance
Evgen [1.6K]
D. distance

A light-year is the distance light would travel in 1 year.
6 0
3 years ago
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A cat is shot horizontally out of a cannon that is on top of a 125 meter tall cliff. If the cat lands 286 m away from the base o
Elden [556K]

The initial velocity of the cat is 56.6 m/s

Explanation:

The motion of the cat is a projectile motion, consisting of:

- a uniform horizontal motion with constant velocity

- a vertical accelerated motion with constant acceleration (free fall)

We start by analyzing the vertical motion, to find the time it takes for the cat to reach the ground. We use the following suvat equation:

s=ut+\frac{1}{2}at^2

where we have (choosing downard as positive direction)

s = 125 m is the vertical displacement of the cat

u = 0 is the initial vertical velocity

t is the time taken to reach the ground

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t, we find

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(125)}{9.8}}=5.05 s

Now we can analzye the horizontal motion. Since the motion is uniform and the horizontal velocity is constant, it is given by

v_x =\frac{d}{t}

where

d = 286 m is the horizontal distance travelled

t = 5.05 s is the time taken

Solving the equation,

v_x = \frac{286}{5.05}=56.6 m/s

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

3 0
3 years ago
While playing football, Chris runs 4.5 m at 20⁰ south of west. If an opponent was trying to tackle him how far west and south wo
rewona [7]

Answer:

South = 1.5m

West =4.2m

Explanation:

Kindly see attached a rough draft of the situation

Step one

Given data

From the sketch the direction of the player is along the resultant of the triangle, corresponding to the Hypotenuse

Step two:

Hence for an opponent to tackle him towards the south, he must be at

sin θ= opp/hyp

sin 20=x/4.5

x=sin 20*4.5

x=0.342*4.5

x= 1.5m

Also, for an opponent to tackle him towards the south, he must be at

cos θ= adj/hyp

cos 20=y/4.5

y=cos 20*4.5

y=0.93*4.5

y= 4.2m

5 0
3 years ago
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