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lawyer [7]
3 years ago
8

A merry-go-round with a a radius of R = 1.9 m and moment of inertia I = 209 kg-m2 is spinning with an initial angular speed of ω

= 1.63 rad/s in the counter clockwise direection when viewed from above. A person with mass m = 73 kg and velocity v = 4.8 m/s runs on a path tangent to the merry-go-round. Once at the merry-go-round the person jumps on and holds on to the rim of the merry-go-round.
What is the magnitude of the initial angular momentum of the merry-go-round?
Physics
1 answer:
RideAnS [48]3 years ago
8 0

Answer:

340.67 kgm²/s

Explanation:

R = Radius of merry-go-round = 1.9 m

I = Moment of inertia = 209 kgm²

\omega_i = Initial angular velocity = 1.63 rad/s

m = Mass of person = 73 kg

v = Velocity = 4.8 m/s

Initial angular momentum is given by

L=I\omega_i\\\Rightarrow L=209\times 1.63\\\Rightarrow L=340.67\ kgm^2/s

The initial angular momentum of the merry-go-round is 340.67 kgm²/s

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Answer:

T = 69^o C

Explanation:

Here at thermal equilibrium we can say that thermal energy given by Hot coffee is equal to the thermal energy absorbed by ice cubes

So here we have

Q_{ice} = Q_{coffee}

now since ice cubes are added into coffee when it is at melting temperature

So here we can say that final temperature of coffee is T degree C

Now we have

m_1L + m_1c_1\Delta T_1 = m_2c_2\Delta T_2

here we have

m_1 = 15 gram

L = 333 kJ/kg = 333 J/g[/tex]

c_1 = c_2 = 4186 J/kg C = 4.186 J/g C

\Delta T_1 = T - 0

\Delta T_2 = 85 - T

now we have

15(333) + 15(4.186)(T - 0) = 140(4.186)(85 - T)

4995 + 62.79T = 49813.4 - 586.04T

648.83 T = 44818.4

T = 69^o C

6 0
3 years ago
What is ohms law <br><br><br>PLEASE ANSWER THIS I NEED IT FAST ​
Lorico [155]

Answer:

Ohms law states that current is directly proportional to the potential difference across the ends of a conductor provided that temperature and other factors kept constant

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6 0
3 years ago
The radius of earth is 6,370,000 m. Express this measurement in km in scientific notation with the correct number of significant
AlexFokin [52]

Answer:

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Explanation:

given,

Radius of earth = 6,370,000 m

we know,

1 km = 1000 m

1 m = 0.001 Km

6,370,000 m =  6,370,000 x 0.001

                       = 6,370 Km

The number 6,370 has 3 significant figure.

To transform this to an exponential number, it is necessary to move the decimal to the left so there is only one digit in front of the decimal point.

Representing the given number in scientific notation

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Speed = Distance /time

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