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Roman55 [17]
3 years ago
9

Lynn rubs a balloon with a piece of wool, which causes the balloon to pick up some of the electric charges from the wool. Lynn t

hen observes that the balloon temporarily sticks to a wall. After several seconds, the balloon falls to the ground. Which best describes the forces in this scenario?
The strong force causes the balloon to stick to the wall, and the weak force causes the balloon to fall to the ground.
The weak force causes the balloon to stick to the wall, and the strong force causes the balloon to fall to the ground.
The electromagnetic force causes the balloon to stick to the wall, and gravitational force causes the balloon to fall to the ground.
Gravitational force causes the balloon to stick to the wall, and electromagnetic force causes the balloon to fall to the ground.
Physics
2 answers:
Softa [21]3 years ago
6 0

Answer:

C

Explanation:

The electromagnetic force causes the balloon to stick to the wall, and gravitational force causes the balloon to fall to the ground.

Hitman42 [59]3 years ago
5 0

Answer:

electrostatics

gravitational forces

Explanation:

rubbing the ballon leads to it acquiring charges that are opposite to that in the wall.the electostatic forces attract the ballon to the wall and tyhe gravitational pull later acts on the ballon causing it to fall down

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pentagon [3]

Answer:

\theta = 67.22 degree

Explanation:

Let say the ball is projected at an angle with horizontal

So here two components of the velocity of the ball is given as

v_x = 8.15 cos\theta

v_y = 8.15 sin\theta

now the displacement in x direction is given as

x = v_x t

4.57 = (8.15 cos\theta)t

in y direction it is given as

y = y_o + v_y t - \frac{1}{2}gt^2

3.05 = 2.44 + (8.15 sin\theta) t - 4.9 t^2

now from above two equations

0.61 = 4.57 tan\theta - 4.9(\frac{4.57}{8.15 cos\theta})^2

0.61 = 4.57 tan\theta - 1.54(1 + tan^2\theta)

1.54 tan^2\theta - 4.57 tan\theta + 2.15 = 0

\theta = 67.22 degree

7 0
3 years ago
A fisherman casts his lure at an angle of 33 degrees above the horizontal. The lure reaches a maximum height of 2.3 m. Assuming
omeli [17]

Answer:

12.32 m/s

Explanation:

Using the formula of maximum height of a projectile,

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Given: H = 2.3 m, Ф = 33°, g = 9.8 m/s²

Substitute into equation 2

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u =√ [45.08/(0.545)²]

u = 45.08/0.297

u = √(151.785)

u = 12.32 m/s

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