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Mrac [35]
4 years ago
10

In which one of the following situations is zero net work done? A) A ball rolls down an inclined plane. B) A physics student str

etches a spring. C) A projectile falls toward the surface of Earth. D) A box is pulled across a rough floor at constant velocity. E) A child pulls a toy across a rough surface causing it to accelerate.
Physics
2 answers:
spayn [35]4 years ago
8 0

Answer:

D

Explanation:

I have taken the test and yeah love ya

lidiya [134]4 years ago
6 0

Answer:

Option D

Explanation:

The work done can be given by the mechanical energy used to do work, i.e., Kinetic energy and potential energy provided to do the work.

In all the cases, except option D, the energy provided to do the useful work is not zero and hence work done is not zero.  

In option D, the box is being pulled with constant velocity, making the acceleration zero and thus Kinetic energy of the system is zero. Hence work done in this case is zero.

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A 5.0 kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 3.0 m/s^2, find the force
Harman [31]
We know that m = 5 kg 
                      a  =  3.0 m/s^2
                      g = 9.8 (since not written, lets assume it's an international standard) 

T - mg =  ma

T = mg + ma

T = (5 . 9.8)  +  (5 . 3 )   

T = 49 + 15
  
T  = 64 N

Hope this helps

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Galina-37 [17]

Answer:

The answer is C

Explanation:

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7 0
3 years ago
The time between high and low tide when the current changes direction is called ____.
Taya2010 [7]
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5 0
3 years ago
Three capacitors, C1 = 2 μF, C2 = 4 μF, C3 = 4 μF, are connected in series Determine the capacitance of a single capacitor that
julsineya [31]

Answer:

1 μF

Explanation:

To obtain the answer to the question, all we need to do is to calculate the equivalent capacitance of the capacitors. This can be obtained as illustrated below.

From the question given above, the following data were obtained:

Capacitor 1 (C₁) = 2 μF

Capacitor 2 (C₂) = 4 μF

Capacitor 3 (C₃) = 4 μF

Equivalent capacitance (Cₑq) =?

Cₑq = 1/C₁ + 1/C₂ + 1/C₃

Cₑq = 1/2 + 1/4 + 1/4

Cₑq = (2 + 1 + 1)/4

Cₑq = 4/4

Cₑq = 1 μF

Thus, the answer to the question is 1 μF

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3 years ago
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