Answer:
a) On Earth
490N
b) On the Moon
85N
c) On Mars
185N
d)in outer space traveling with constant velocity.
0
Explanation:
The weight is defined as:
(1)
Where m is the mass and g is the gravity
a) On Earth 
Then, equation 1 can be used:


but 1N = Kg.m/s^{2}

Hence, the weight of the astronaut on Earth is
b) On the Moon 


Hence, the weight of the astronaut on the Moon is 
c) On Mars 


Hence, the weight of the astronaut on Mars is 
(d) in outer space traveling with constant velocity.
Tanking into consideration that the astronaut is traveling in outer space at a constant velocity, it can be concluded that the acceleration will be zero.
Remember that the acceleration is defined as:

Since the acceleration is the variation of the velocity in a unit of time.
Therefore, from equation 1 is gotten.

Remember that g is the acceleration that a body experience as a consequence of the gravitational field.
