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Mrac [35]
3 years ago
10

In which one of the following situations is zero net work done? A) A ball rolls down an inclined plane. B) A physics student str

etches a spring. C) A projectile falls toward the surface of Earth. D) A box is pulled across a rough floor at constant velocity. E) A child pulls a toy across a rough surface causing it to accelerate.
Physics
2 answers:
spayn [35]3 years ago
8 0

Answer:

D

Explanation:

I have taken the test and yeah love ya

lidiya [134]3 years ago
6 0

Answer:

Option D

Explanation:

The work done can be given by the mechanical energy used to do work, i.e., Kinetic energy and potential energy provided to do the work.

In all the cases, except option D, the energy provided to do the useful work is not zero and hence work done is not zero.  

In option D, the box is being pulled with constant velocity, making the acceleration zero and thus Kinetic energy of the system is zero. Hence work done in this case is zero.

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Find the pressure exerted on the floor by a 100N box whose bottom area is 40cm x<br> 50cm.
Mazyrski [523]

<u>Answer:</u>

Pressure exerted = 500 Pa

<u>Explanation:</u>

The formula for pressure is as follows:

Pressure = \frac{Force \space\ applied}{Area}

In this case,

Force applied = 100N

Area = 40cm × 50cm = 2000cm² = 2000 × 10⁻⁴ = 0.2m²

Substituting these values into the formula:

Pressure = \frac{100}{0.2}

⇒ Pressure = 500 Pa

3 0
2 years ago
Read 2 more answers
The electron's velocity at that instant is purely horizontal with a magnitude of 2 \times 10^5 ~\text{m/s}2×10 ​5 ​​ m/s then ho
Lesechka [4]

Complete question:

At a particular instant, an electron is located at point (P) in a region of space with a uniform magnetic field that is directed vertically and has a magnitude of 3.47 mT. The electron's velocity at that instant is purely horizontal with a magnitude of 2×10​⁵​​ m/s then how long will it take for the particle to pass through point (P) again? Give your answer in nanoseconds.

[<em>Assume that this experiment takes place in deep space so that the effect of gravity is negligible.</em>]

Answer:

The time it will take the particle to pass through point (P) again is 1.639 ns.

Explanation:

F = qvB

Also;

F = \frac{MV}{t}

solving this two equations together;

\frac{MV}{t} = qVB\\\\t = \frac{MV}{qVB} = \frac{M}{qB}

where;

m is the mass of electron = 9.11 x 10⁻³¹ kg

q is the charge of electron = 1.602 x 10⁻¹⁹ C

B is the strength of the magnetic field = 3.47 x 10⁻³ T

substitute these values and solve for t

t = \frac{M}{qB} = \frac{9.11 *10^{-31}}{1.602*10^{-19}*3.47*10^{-3}} = 1.639 *10^{-9}  \ s \ = 1.639 \ ns

Therefore, the time it will take the particle to pass through point (P) again is 1.639 ns.

5 0
3 years ago
How long will a trip take in hours of you travel 450kmat an average speed of 80 km/hr
777dan777 [17]
5.625 hours and it is 450 divided by 80
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4 0
3 years ago
Is it possible to have sex then after a week you get your periods and get pregnant?
mrs_skeptik [129]

Answer:

Yes it stilll possible

Explanation:

7 0
2 years ago
A force of 30 N is applied to an object with a mass of 15 kg. What is the resulting acceleration?
svet-max [94.6K]

Answer:

We know that Force = mass × acceleration

By substituting the values we get,

30 N = 15 kg × a (where a is acceleration)

Or we can write it as

15 kg × a = 30 N

Transposing 15 to RHS,

a = 30 ÷ 15 m/s²

Therefore, acceleration = 2 m/s²

pls give brainliest for the answer

5 0
2 years ago
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