The speed stops as it hits the girls hand but speed reduces as it reaches her hand and increases at the beginning of the movement
Answer:
F = 15.47 N
Explanation:
Given that,
Q = 52 µC
q = 10 µC
d = 55 cm = 0.55 m
We need to find the magnitude of the electrostatic force on q. The formula for the electrostatic force is given by :

So, the magnitude of the electrostatic force is 15.47 N.
What happens when the light hits the glass depends on what it was in before it hit the glass.
WHILE it's in the glass, the speed of light doesn't change.
The maximum height of the object when thrown at the speed of 20 m/s is 20 m.
What is speed?
Speed is the magnitude of the rate of change of the position of any object with time which is a scalar quantity. It is the ratio of speed by time with the unit m/s or cm/s.
The height this object can travel with initial speed of 20 m/s can be calculated as,
<u>v^2 = u^2 + 2as</u>
where v is the final velocity, u is the initial velocity a is the acceleration due to gravity s is height.
0 = 20^2 + 2 (-10) s
s = 400 / 20 = 20 m
Therefore, the maximum height the object can travel with initial speed of 20 m/s is 20m.
To learn more about the speed click on the given link brainly.com/question/13943409
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Answer:
15.64 KN
Explanation:
mass of the elevator cab with a single occupant= 2300 kg
acceleration relative to the cab
= 6.80 m/s^2
acceleration of the coin relative to the cab in the opposite direction of motion of cab so we can consider it as a= -6.80 m/s^2
The acceleration of elevator cab relative to the ground 
now we can say that

=-6.80+ a_{eg}= -9.8
[tex]a_{eg}=-9.8+6.80=-3.8
The forces that act on elevator cab are tension and gravitational, applying newtons second law
T- mg= ma_{eg}
Then the tension in the cable is
T= 2300(-3.8)+2300×9.8= 15640 N= 15.64 KN
therefore tension in the string will be 15.64 KN