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3 years ago

15

What type of motion occurs when an object spends around and axis without altering its linear position?

1 answer:

ch4aika [34]3 years ago

7 0

I believe it is called centripetal force <span />

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The difference between an electric motor and an electric generator is that a motor converts _______ energy into energy _______,

lianna [129]

Answer:

Motor converts Electrical energy into Mechanical Energy, while A generator converts Mechanical energy into Electrical energy. thankyou

Explanation:

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3 years ago

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The equation most often associated with Newton's Second Law of Motion is<br> Answer here

zloy xaker [14]

Answer: F=ma

Explanation:

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3 years ago

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Antimony is like a nonmetal in that it is a brittle, crystalline solid, has poor electrical and heat conductivity, and has a low

Reil [10]

Answer is B. It is a metalloid.

Metalloid is a chemical element that has characteristics of both metals and non- metals.

Antimony is brittle,is a poor conductor of heat and electricity,has a low boiling point and is a crystalline solid. These are some of the characteristics which a non-mechanical has.

It can also be classified as a metal due to its ability to form alloys easily and due to it's shiny silver appearance.Antimony alloys are used in batteries.

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4 years ago

Two Earth satellites, A and B, each of mass m = 940 kg , are launched into circular orbits around the Earth's center. Satellite

-Dominant- [34]

Answer:

The required work done is $6.5\times10^{9}\ J$

Explanation:

Given that,

Mass of each satellites = 940 kg

Altitude of A = 4500 km

Altitude of B = 11100 km

We need to calculate the potential energy

Using formula of potential

$U_{A}=-\dfrac{Gm_{A}m_{E}}{r_{A}}$

Put the value into the formula

$U_{A}=-\dfrac{6.67\times10^{-11}\times940\times5.98\times10^{24}}{6.38\times10^{6}+4.50\times10^{6}}$

$U_{A}=-3.44\times10^{10}\ J$

We need to calculate the potential energy

Using formula of potential

$U_{B}=-\dfrac{Gm_{B}m_{E}}{r_{A}}$

Put the value into the formula

$U_{B}=-\dfrac{6.67\times10^{-11}\times940\times5.98\times10^{24}}{6.38\times10^{6}+11.10\times10^{6}}$

$U_{B}=-2.14\times10^{10}\ J$

We need to calculate the value of $k_{A}$

Using formula of $k_{A}$

$k_{A}=-\dfrac{1}{2}U_{A}$

Put the value into the formula

$k_{A}=\dfrac{1}{2}\times3.44\times10^{10}$

$k_{A}=1.72\times10^{10}\ J$

We need to calculate the value of $k_{B}$

Using formula of $k_{B}$

$k_{B}=-\dfrac{1}{2}U_{B}$

Put the value into the formula

$k_{B}=\dfrac{1}{2}\times2.14\times10^{10}$

$k_{B}=1.07\times10^{10}\ J$

We need to calculate the work done

Using formula of work done

$W=\Delta K+\Delta U$

$W=(k_{B}-k_{A})+(U_{B}-U_{A})$

$W=(-\dfrac{U_{B}}{2}+\dfrac{U_{A}}{2})+(U_{B}-U_{A})$

$W=\dfrac{1}{2}(U_{B}-U_{A})$

Put the value into the formula

$W=\dfrac{1}{2}\times(-2.14\times10^{10}+3.44\times10^{10})$

$W=6.5\times10^{9}\ J$

Hence, The required work done is $6.5\times10^{9}\ J$

7 0

3 years ago

When large amplitude sound vibrates the ear significantly, a _______ results.

kondaur [170]

D loud sound

Hope this helped:)

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3 years ago

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