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ratelena [41]
4 years ago
12

Why do the graphs differ?​

Physics
1 answer:
melisa1 [442]4 years ago
3 0

Well first graph represents rectangular hyperbola

vu = c^2 ( c is constant)

AS 1/v + 1/u = 1/f

Take1/ f to be constant c

1/v = c - 1/u

it is of the form y = - x + k

Slope = -1 having intercept k as shown in fig 2

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In a mattress test, you drop a 7.0 kg bowling ball from a height of 1.5 m above a mattress, which as a result compresses 15 cm a
Assoli18 [71]

Answer:

(c) 10.29 J

(d) 113.19 J

(e) 113.19 J

(f) 10061 N/m

Explanation:

15 cm = 0.15 m

Let g = 9.8 m/s2

(c) The work done by gravitational force is the product of gravity force and the distance compressed

E_p = mgx = 7*9.8*0.15 = 10.29 J

(d) By using law of energy conservation with potential energy reference being 0 at the maximum compression point. As the ball falls and come to a stop at the compression point, its potential energy is transferred to elastic energy, which is the work that the mattress does on the ball:

E_p = E_e

E_e = mgh

where h = 1.5 + 0.15 = 1.65 m is the vertical distance that it falls.

E_e = 7*9.8*1.65 = 113.19 J

(e) Before the compression, the potential energy of the mattress is 0. After the compression, the potential energy is 113.19J. So it has increased by 113.19J due to the potential energy transferred from the falling ball.

(f) E_e = 113.19 = kx^2/2

k0.15^2/2 = 113.19

k = 10061 N/m

8 0
3 years ago
Read 2 more answers
Are cells made of tisse?
zepelin [54]

Answer:

Yes

Explanation:

Cells make up tissues. Hope this helped

5 0
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In a car collision, is it better for the passenger if the change in momentum is over a short period of time or a long period of
e-lub [12.9K]

Explanation:

The force on the passenger will be F = ma

Here, m does not change, but a is the variable.

If the cars slows down very fast, the acceleration will be higher, and thus the force will be higher.

If the acceleration is lower, the force will be lower as well, which would be the most desirable scenario for the passenger.

5 0
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A rock with a mass of 25 kg has a weight of 40.8 n on the moon. what is the value of the acceleration of gravity (g) on the moon
zaharov [31]
Mass m = 25 Kg;  Force = Weight = mg   Force = ma  but a = g

          F = 40.8 N

Required: gravity g = ?

                F = mg

                g = F/m

                g = 40.8 N/25 Kg

                g = 1.6 m/s²
7 0
4 years ago
a circular cylinder and isused to maintain a water depth of 4 m. That is, when the water depth exceeds 4 m, thegate opens slight
stiv31 [10]

Answer:

  W / A = 39200 kg / m²

Explanation:

For this problem let's use the equilibrium equation of / newton

           F = W

Where F is the force of the door and W the weight of water

         W = mg

We use the concept of density

        ρ = m / V

        m = ρ V

The volume of the water column is

          V = A h

We replace

         W = ρ A h g

On the other side the cylinder cover has a pressure

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          F = P A

We match the two equations

       P A = ρ A h g

        P = ρ g h

        P = 39200 Pa

The weight of the water column is

       W  = 1000 9.8 4 A

       W / A = 39200 kg / m²

3 0
4 years ago
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