Hey there, the answer is .............................. About 0.7 m/sec^2
<span>
Acceleration is the change in speed / time </span>
<span>Change in speed is 60 m/sec </span>
<span>Time is 1 minute 25 second. Convert that to seconds. </span>
<span>Divide the change in speed by the time in seconds.
About 0.7 m/sec^2
</span><span>So the acceleration is - 60 / 85 = - 0.71 m/s^2
HOPE I HELPED!!!!!!!!!!</span>
Since an alpha particle has 2 protons and no negative particles (electrons) to balance the net charge, its charge is
Q=2(1.6e-19)=3.2e-19C.
The force on a charged particle is F=QE so
(3.2e-19C)(600N/C)=1.92e-16N
The final velocity of the truck is found as 146.969 m/s.
Explanation:
As it is stated that the lorry was in standstill position before travelling a distance or covering a distance of 3600 m, the initial velocity is considered as zero. Then, it is stated that the lorry travels with constant acceleration. So we can use the equations of motion to determine the final velocity of the lorry when it reaches 3600 m distance.
Thus, a initial velocity (u) = 0, acceleration a = 3 m/s² and the displacement s is 3600 m. The third equation of motion should be used to determine the final velocity as below.

Then, the final velocity will be

Thus, the final velocity of the truck is found as 146.969 m/s.
The answer is 59.4 degrees.