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Semmy [17]
3 years ago
11

What are the alkali metals?

Chemistry
2 answers:
Andre45 [30]3 years ago
8 0

Answer:

they are the first group in the periodic table

Explanation:

its on the far left of the table- this is the apex answer

abruzzese [7]3 years ago
4 0

Answer:

Are the six chemical elements

Explanation:

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What do we need to know about a molecule in order to carry out molarity calculations
professor190 [17]

Answer the type of cell

Explanation:

7 0
3 years ago
You find a little bit (0.150g) of a chemical marked Tri-Nitro-Toluene. Upon complete combustion in oxygen, you collect 0.204 g o
Elan Coil [88]

Answer:

The empirical formula is C7H5N3O6  

Explanation:

Step 1: Data given

Mass of sample = 0.150 grams

Mass of CO2 = 0.204 grams

Molar mass CO2 = 44.01 g/mol

Mass of H2O = 0.030 grams

Molar mass H2O = 18.02 g/mol

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Molar mass O = 16.0 g/mol

Step 2: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 0.204 grams / 44.01 g/mol

Moles CO2 = 0.00464 moles

Step 3: Calculate moles C

For 1 mol CO2 we have 1 mol C

For 0.00464 moles we have 0.00464 moles C

Step 4: Calculate mass C

Mass C = 0.00464 moles * 12.01 g/mol

Mass C = 0.0557 grams

Step 5: Calculate moles H2O

Moles H2O = 0.030 grams / 18.02 g/mol

Moles H2O = 0.00166 moles

Step 6: Calculate moles H

For 1 mol H2O we have 2 moles H

For 0.00166 moles H2O we have 2* 0.00166 = 0.00332 moles H

Step 7: Calculate mass H

Mass H = 0.00332 moles * 1.01 g/mol

Mass H = 0.00335 grams

Step 8: Calculate mass N

Mass N = 0.185 * 0.150 grams

Mass N = 0.02775 grams

Step 9: Calculate moles N

Moles N = 0.02775 grams / 14.0 g/mol

Moles N = 0.00198 moles

Step 10: Calculate mass O

Mass O = 0.150 grams - 0.02775 - 0.00335 - 0.0557

Mass O = 0.0632 grams

Step 11: Calculate moles O

Moles O = 0.0632 grams / 16.0 g/mol

Moles O = 0.00395 moles

Step 11: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.00464 moles / 0.00198 moles =2.33

H: 0.00332 moles / 0.00198 moles = 1.66

N: 0.00198 moles / 0.00198 moles = 1

O: 0.00395 moles / 0.00198 moles = 2

For 1 mol N we have 2.33 moles C, 1.66 moles H and 2 moles O

OR

For 3 moles N we have 7 moles C, 5 moles H and 6 moles O

The empirical formula is C7H5N3O6  

5 0
3 years ago
What happens if more product is added to a system at equalibrium
telo118 [61]

Answer:

When additional product is added, the equilibrium shifts to reactants to reduce the stress. If reactant or product is removed, the equilibrium shifts to make more reactant or product, respectively, to make up for the loss.

5 0
3 years ago
Draw the structure of ozone according to VSEPR theory. What would be its associated molecular geometry?
vodka [1.7K]

Answer: Ozone's molecular geometry can be described as bent.

Explanation:

The molecular geometry of the O3 groups has a trigonal planar arrangement.

Here is a quick explanation of the molecular geometry of O3 including a quick description of the O3 bond angles.

Examining the  Lewis structure of  O3 we can see that there are a pair of unbounded valence electrons at the top of the structure.

Based on VSEPR Theory (Valence Shell Electron Pair Repulsion Theory) these electrons will repel the electron clouds of the two oxygen atoms on the end.

As a result they will be pushed down giving the 03 molecule a bent molecular geometry or shape.

The 03 bond angle will be 116° degrees since it has a Bent molecular geometry

8 0
3 years ago
How many monochlorination products can be formed (constitutional isomers only) from the reaction of (CH3)2CHCH2CH3 with Cl2 and
faltersainse [42]

Answer:

4 monochlorination products can be formed.

Explanation:

Constitutional isomers : These are those compounds with same molecular formula but different atomic arrangement.For example: butane and 2-methly-propane.

On monochlorination of 2 methyl-butane  we will have four possibilities of product which will be constitutional isomers of each other:

  • 1-chloro-3-methyl butane : (CH_3)_2CH-CH_2-CH_2-Cl
  • 2-chloro-3-methyl butane : (CH_3)_2CH-CHCl-CH_3
  • 2-chloro-2-methyl butane (CH_3)_2CCl-CH_2-CH_3
  • 1-chloro-2-methyl butane (CH_2Cl)_2CH-CH_2-CH_3
7 0
3 years ago
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